我已经尝试过许多指南中的解决方案,为我的loglog
情节绘制最佳拟合线,但我不断得到一条似乎具有正确斜率的线,但y-intercept也是如此大。该图表绘制在最后一块代码中。
剧情的截图示例:
N=2; % Starting/current matrix size
M=1; % Number of trials per matrix
incr=2; %matrix size increment
reps=20; %number of increments
all_errs=zeros(reps,1); %vector of mean erros for each N
used_N=zeros(reps,1); %values of N used for plot
%find M such that max margin of error <0.01 for confidence interval
desired_margin=0.01; %desired margin of error
conf=0.98; %value for confidence interval
curr_margin=conf/sqrt(M); %current margin of error
while curr_margin>=desired_margin
M=M+1;
curr_margin=conf/sqrt(M);
end
for h=1:reps
used_N(h)=N; %add current value of N to list of used N values
errs=zeros(M,1); % Vector of errors
x=ones(N,1); % exact solution vector
for i=1:M
A=spdiags(rand(N,3), -1:1, N,N); %constructs tridiagonal matrx with random entries
b=A*x; % Compute the right-hand side vector
z=A\b; % Solve the linear system
errs(i)=max(abs(z-x)); % Compute the error
end
mean_err=mean(errs);
all_errs(h)=mean(errs);
N=N+incr; %increments N
end
%disp(all_errs)
p=polyfit(log10(used_N), log10(all_errs), 1); %fits line to data
fit=exp(polyval(p,log10(used_N))); %y-coordinates of best fit line
loglog(used_N, all_errs, 'o',used_N,fit,'-'); %plots the error versus N in a loglog plot w/best fit line
title(['Log-Log Plot for Matrix Size vs. Mean Error'],'fontsize',14)
xlabel('log_{10}(Size of Matrix)','fontsize',12)
ylabel('log_{10}(Mean Error)','fontsize',12)