float __stdcall (*pFunc)(float a, float b) = (float (__stdcall *)(float,float))0x411280;
如何使用调用约定声明函数指针？上面给出了一个错误。
答案 0 :(得分：37)
诀窍是将__stdcall放在括号内，如下所示：
float (__stdcall *pFunc)(float a, float b) = (float (__stdcall *)(float,float))0x411280;
当然，建议您使用typedef，但同样的技巧适用：
typedef float (__stdcall *FuncType)(float a, float b);
答案 1 :(得分：1)
WHERE是编译器最接受的形式。一些编译器接受lag as (
select *, LAG(tier) OVER (PARTITION BY account_id ORDER BY date ASC) AS previous_plan
, LAG(date) OVER (PARTITION BY account_id ORDER BY date ASC) AS previous_plan_date
from data
)
SELECT *
FROM lag
where (current_plan = 'free' and previous_plan in ('monthly', 'yearly'))
和 answerQuestions() {
if (this.shift.getEarly() && (this.shift.getTimeToStart().asHours() > environment.alertTimes.answerQuestions)) {
var timeTo = this.durationFormatPipe.transform(this.shift.getStart());
var message = 'Your shift starts ' + timeTo + ', are you sure you want to answer questions now?';
setTimeout(() => {
this.alertService.confirmOrCancelAlert('You are early!', message, () => {
this.doAnswerQuestions();
});
}, 50);
} else {
this.doAnswerQuestions();
}
}
甚至int (__cdecl **func)()。 Clang接受所有3种形式并将其正确解释为类型int __cdecl (**func)(int)
在clang上引入int (**__cdecl func)(int)指针也不会改变图片，并且只要const在指针之后即可接受任何排列
int (*__cdecl *func)(int)答案 2 :(得分：0)
__fastcall是优化的（最快的调用约定），但未用于未知原因
尝试：
int (__fastcall *myfunction)(int,float);