我目前正在处理一个带有react的项目,我在使用setState方法时遇到了合并两个对象的问题。我有两个类似于
的对象person1 = {
name: 'ramya',
age: 21,
gender: 'f',
skills:{
technicalSkills: {
languages: ['C', 'C++', 'Java'],
operatingSystems: ['Unix', 'Linux']
},
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English']
}
},
}
obj2 = {
skills: {
linguisticSkills: {
toRead: ['English', 'Tamil']
}
}
}
我想改变人1的技能状态。语言技能为
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English', 'Tamil']
}
skills.linguisticSkills.toSpeak
和skills.linguisticSkills.toRead
不断变化,即添加或删除项目。每当它发生变化时,如何在setState中合并person1和obj2,以便最终处于正确的状态?
更新 _.merge因为这样的情况而失败:
person1 = {
name: 'ramya',
age: 21,
gender: 'f',
skills:{
technicalSkills: {
languages: ['C', 'C++', 'Java'],
operatingSystems: ['Unix', 'Linux']
},
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English', 'Tamil', 'Telugu']
}
},
}
obj2 = {
skills: {
linguisticSkills: {
toRead: ['English', 'Tamil']
}
}
}
它给出与人1相同的结果,而
{
name: 'ramya',
age: 21,
gender: 'f',
skills:{
technicalSkills: {
languages: ['C', 'C++', 'Java'],
operatingSystems: ['Unix', 'Linux']
},
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English', 'Tamil']
}
},
}
预计。
答案 0 :(得分:4)
Lodash的_.merge()
是递归的。如果您需要对合并过程进行更精细的控制,可以使用_.mergeWith()
。
if UIImagePickerController.isSourceTypeAvailable(.photoLibrary) {
let imagePicker = UIImagePickerController()
imagePicker.delegate = refrenceViewController as! UIImagePickerControllerDelegate & UINavigationControllerDelegate
imagePicker.sourceType = .photoLibrary;
imagePicker.allowsEditing = true
refrenceViewController.present(imagePicker, animated: true, completion: nil)
}
const person1 = {"name":"ramya","age":21,"gender":"f","skills":{"technicalSkills":{"languages":["C","C++","Java"],"operatingSystems":["Unix","Linux"]},"linguisticSkills":{"toSpeak":["English","Tamil"],"toRead":['English', 'Tamil', 'Telugu']}}}
const obj2 = {"skills":{"linguisticSkills":{"toRead":["English","Tamil"]}}}
const result = _.mergeWith({}, person1, obj2, (objValue, srcValue) => {
if( _.isArray(srcValue)) {
return srcValue;
}
});
console.log(result);
答案 1 :(得分:0)
查看https:How to deep merge instead of shallow merge?
/**
* Simple object check.
* @param item
* @returns {boolean}
*/
export function isObject(item) {
return (item && typeof item === 'object' && !Array.isArray(item));
}
/**
* Deep merge two objects.
* @param target
* @param ...sources
*/
export function mergeDeep(target, ...sources) {
if (!sources.length) return target;
const source = sources.shift();
if (isObject(target) && isObject(source)) {
for (const key in source) {
if (isObject(source[key])) {
if (!target[key]) Object.assign(target, { [key]: {} });
mergeDeep(target[key], source[key]);
} else {
Object.assign(target, { [key]: source[key] });
}
}
}
return mergeDeep(target, ...sources);
}
// Code copied from linked Stack Overflow question
// https://stackoverflow.com/questions/27936772/how-to-deep-merge-instead-of-shallow-merge
// Answer by Salakar:
// https://stackoverflow.com/users/2938161/salakar