Question

我有一个问题，我现在很长一段时间都在苦苦挣扎。我有两个数组：

var arr1 = [{"x":1,"y":1,"value":null},{"x":2,"y":1,"value":null},{"x":3,"y":1,"value":null},{"x":4,"y":1,"value":null},{"x":5,"y":1,"value":null},{"x":1,"y":2,"value":null},{"x":2,"y":2,"value":null},{"x":3,"y":2,"value":null},{"x":4,"y":2,"value":null},{"x":5,"y":2,"value":null},{"x":1,"y":3,"value":null},{"x":2,"y":3,"value":null},{"x":3,"y":3,"value":null},{"x":4,"y":3,"value":null},{"x":5,"y":3,"value":null},{"x":1,"y":4,"value":null},{"x":2,"y":4,"value":null},{"x":3,"y":4,"value":null},{"x":4,"y":4,"value":null},{"x":5,"y":4,"value":null},{"x":1,"y":5,"value":null},{"x":2,"y":5,"value":null},{"x":3,"y":5,"value":null},{"x":4,"y":5,"value":null},{"x":5,"y":5,"value":null}];

var arr2 = [{"x":1,"y":1,"value":13},{"x":1,"y":3,"value":3},{"x":2,"y":2,"value":146},{"x":2,"y":3,"value":44},{"x":2,"y":4,"value":42},{"x":2,"y":5,"value":5},{"x":3,"y":2,"value":14},{"x":3,"y":3,"value":57},{"x":3,"y":4,"value":23},{"x":3,"y":5,"value":15},{"x":4,"y":2,"value":1},{"x":4,"y":3,"value":4},{"x":4,"y":4,"value":8},{"x":4,"y":5,"value":1},{"x":5,"y":4,"value":1},{"x":5,"y":5,"value":8}];

arr1总是包含25个对象，arr2包含可变数量的对象，但它们的格式始终相同。

如何将两个数组合并为一个数组，例如：

结果，来自arr1的

{"x":1,"y":1,"value":null}将是{"x":1,"y":1,"value":13}，但arr1中的{"x":2,"y":1,"value":null}将保持不变，因为arr2没有此对象。

合并之后，最理想的是拥有一个包含25个对象的数组，其中字段"value"从arr2中的对象中填充。

修改好吧，因为我得到了很多downvotes，你可以在JSFiddle

找到我的代码

非常感谢任何帮助！

Answer 1

如果这是一个选项，您可以使用jQuery extend来实现此目的。

var extendedArray = $.extend({}, arr1, arr2);

上面的代码将为您创建一个新对象，其中包含您请求的内容。如果您不想要新对象，请使用

$.extend(arr1, arr2);

请参阅上面提到的文档以获取更多信息（例如深度扩展等）。

合并两个对象数组

1 个答案: