Question

我的查询以下列方式显示结果：

{"declined": [{"2018-01-16": 1}], "negative": [{"2018-01-16": 1}], "positive": [{"2018-01-16": 2}]}

查询如下所示：

select 
jsonb_build_object('positive', 
  json_agg(jsonb_build_object(date, positive)) FILTER (WHERE positive <> 0)
) ||
jsonb_build_object('negative',
  json_agg( jsonb_build_object(date, negative)) FILTER (WHERE negative <> 0)
) ||
jsonb_build_object('declined', 
  json_agg(jsonb_build_object(date, declined)) FILTER (WHERE declined <> 0)
)
from (
SELECT
  date(survey_results.created_at) as date,
  COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('high','medium'))) AS positive,
  COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('low'))) AS negative,
  COUNT(*) FILTER (WHERE (coalesce(raw#>>'{survey,denied}','f') = 'true')) AS declined
  FROM survey_results
  GROUP BY date(survey_results.created_at)
) as t1;

我正在尝试重构该查询以返回看起来像这样的json：

{"2018-01-16": {"positive": 2, "declined": "1", "negative": 1}}

我该怎么做？这是你可以试验的sql小提琴：

http://sqlfiddle.com/#!17/a9705/8

提前致谢。

Answer 1

我可能错过了什么 - 我jsonb_build_object只是jsonb_build_object：

select 
jsonb_build_object(date,jsonb_build_object('positive',positive,'negative',negative,'declined',declined))
from (
SELECT
  date(survey_results.created_at) as date,
  COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('high','medium'))) AS positive,
  COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('low'))) AS negative,
  COUNT(*) FILTER (WHERE (coalesce(raw#>>'{survey,denied}','f') = 'true')) AS declined
  FROM survey_results
  GROUP BY date(survey_results.created_at)
) t1

和结果：

{"2018-01-16": {"declined": 1, "negative": 1, "positive": 2}}

以不同格式呈现查询数据 - PostgreSQL

1 个答案: