Question

    $query1 = pg_query('SELECT "id","location",ST_Distance_Sphere(ST_Point(lat,long ), ST_Centroid("path"::geometry)) FROM places 
        ORDER BY ST_Distance_Sphere
        LIMIT 1');

echo $query1

我有一个带有lat和long coardinates的数据库，如果我在phpPgAdmin中运行上面的查询它给了我想要的结果，但是当通过php查询时它没有，它给我“资源7”而不是

我是否正确格式化了上面的查询？

提前感谢AJ。

Answer 1

通过将SQL语句分配给变量，然后回显出变量的值，可以判断SQL语句是否格式正确。您需要回显SQL语句，而不是pg_query（）返回的值。

$ cat code/php/test.php
<?php
    $sql = 'SELECT "id","location",ST_Distance_Sphere(ST_Point(lat,long ), ST_Centroid("path"::geometry)) FROM places ORDER BY ST_Distance_Sphere LIMIT 1';
echo $sql;
$  php code/php/test.php
SELECT "id","location",ST_Distance_Sphere(ST_Point(lat,long ), ST_Centroid("path"::geometry)) FROM places ORDER BY ST_Distance_Sphere LIMIT 1%                  ➜  ~

ST_Point（）的参数顺序是“long，lat”，而不是“lat，long”。如果您的原始查询返回正确的结果，我会有点担心。

Answer 2

我认为问题是echo $ query1

你不能只是回应结果。首先你必须声明一个连接然后你必须用它做一些事情才能打印出来。例如：

$con = pg_connect("host=you_host_db port=5432 dbname=database_name");

$query1 = pg_query($con, 'SELECT "id","location",ST_Distance_Sphere(ST_Point(lat,long ) as a,ST_Centroid("path"::geometry)) as b FROM places ORDER BY ST_Distance_Sphere LIMIT 1');


while ($row = pg_fetch_assoc($query1)) {
    echo $row['id'];
    echo $row['location'];
    echo $row['a'];
    echo $row['b'];
}

postgres中的格式查询

2 个答案: