Question

我有以下CDS：

@AbapCatalog.sqlViewName: 'ZAMPAYERINFO'
@AbapCatalog.compiler.compareFilter: true
@AccessControl.authorizationCheck: #CHECK
@EndUserText.label: 'Read payer information'
define view zam_payer_info
with parameters p_payer: abap.char(10)
as select distinct from knvp 
   join kna1 on
   knvp.kunnr = kna1.kunnr
{
    key knvp.kunnr as Payer,
    kna1.name1 as Name
} where knvp.kunnr like $parameters.p_payer

编译器抱怨：

Comparison value of LIKE condition must be a character-type literalZAM_PAYER_INFO (Data Definition)
As you can see on the CDS code, I am using character-type.

我理解LIKE语句的作用，例如：

@AbapCatalog.sqlViewName: 'ZAMPAYERINFO'
@AbapCatalog.compiler.compareFilter: true
@AccessControl.authorizationCheck: #CHECK
@EndUserText.label: 'Read payer information'
define view zam_payer_info
  with parameters
    p_payer : abap.char(10)
  as select distinct from knvp
    join                  kna1 on knvp.kunnr = kna1.kunnr
{
  key knvp.kunnr as Payer,
      kna1.name1 as Name
}
where
  knvp.kunnr like 'a%'

搜索所有以a开头的kunnr。但我的问题是，如何将它与输入参数p_payer结合起来，最后它应该是LIKE %p_payer，其中p_payer将通过我传递的值替换。

有什么不对？

Answer 1

您可以将输入参数和＆＃39;％＆＃39;组合在一起。 SQLScript for HANA数据库中的以下通配符

declare p varchar(10);
P = 'D';
select * from "A00077387"."ORGANIZATION" where unit like (:p || '%');

你知道，你可以使用＆＃34; ||＆＃34;连接＆＃39;％＆＃39;你的参数

您需要修改WHERE子句，如下所示

knvp.kunnr like ($parameters.p_payer || '%')

我希望它有所帮助，

Answer 2

您可以将ABAP中的类似声明推回去。

BackupWebConfigFile

从此cds视图中选择时：

@AbapCatalog.sqlViewName: 'ZAMPAYERINFO'
@AbapCatalog.compiler.compareFilter: true
@AccessControl.authorizationCheck: #CHECK
@EndUserText.label: 'Read payer information'
define view zam_payer_info
  with parameters
    p_payer : abap.char(10)   // you can remove this also.
  as select distinct from knvp
    join                  kna1 on knvp.kunnr = kna1.kunnr
{
  key knvp.kunnr as Payer,
      kna1.name1 as Name
}
//where
 //knvp.kunnr like 'a%'  remove the kunnr where statement here.

我认为这看起来有点蹩脚。但这是一个解决方案：）

如何从参数值中选择类似于SQL WHERE LIKE的数据

2 个答案: