Question

我有一个带有字段代码的表a和带有字段代码的表b 我需要

a.code   b.code
------   ------
1        4           
2        5          
6        8

表a

code
----
1
2
6

表b

code
----
4
5
8

如何使用单个查询执行此操作？

Answer 1

使用Row_number加CTE。试试这个。

;WITH cte1
     AS (SELECT Row_number()OVER(ORDER BY Code) rn,
                Code
         FROM   table1),
     cte2
     AS (SELECT Row_number()OVER(ORDER BY Code) rn,
                Code
         FROM   table2)
SELECT a.Code,
       b.Code
FROM   cte1 a
       JOIN cte2 b
         ON a.rn = b.rn

或

SELECT a.code,
       b.code
FROM   (SELECT Row_number()OVER(ORDER BY code) rn,
               code
        FROM   table1) a
       INNER JOIN (SELECT Row_number()OVER(ORDER BY code) rn,
                          code
                   FROM   table2) b
               ON a.rn = b.rn

更新：对于Ms-Access，请使用correlated subquery执行此操作

SELECT a.code,
       b.code
FROM   (SELECT code,
               (SELECT Count(1)
                FROM   tablea s
                WHERE  s.code >= f.code) rn
        FROM   tablea f) a
       INNER JOIN (SELECT (SELECT Count(1)
                           FROM   tableb s
                           WHERE  s.code >= f.code) rn,
                          code
                   FROM   tableb f) b
               ON a.rn = b.rn

如何从两个相似的表中选择两个相似的字段？

1 个答案: