我将事件从redis订阅推送到通过websocket连接的客户端。当客户端断开websocket时,我无法取消订阅并退出redis例程。
灵感来自this post,这是我迄今所拥有的。我能够通过websocket接收订阅事件并向客户端发送消息,但是当客户端关闭websocket并且defer close(done)
代码触发时,我的case b, ok := <-done:
不会触发。它似乎被默认情况下重载???
package api
import (
...
"github.com/garyburd/redigo/redis"
"github.com/gorilla/websocket"
)
func wsHandler(w http.ResponseWriter, r *http.Request) {
var upgrader = websocket.Upgrader{
ReadBufferSize: 1024,
WriteBufferSize: 1024,
}
conn, err := upgrader.Upgrade(w, r, nil)
if err != nil {
HandleError(w, err)
return
}
defer conn.Close()
done := make(chan bool)
defer close(done)
for {
var req WSRequest
err := conn.ReadJSON(&req)
if err != nil {
HandleWSError(conn, err)
return
}
defer conn.Close()
go func(done chan bool, req *WSRequest, conn *websocket.Conn) {
rc := redisPool.Get()
defer rc.Close()
psc := redis.PubSubConn{Conn: rc}
if err := psc.PSubscribe(req.chanName); err != nil {
HandleWSError(conn, err)
return
}
defer psc.PUnsubscribe()
for {
select {
case b, ok := <-done:
if !ok || b == true {
return
}
default:
switch v := psc.Receive().(type) {
case redis.PMessage:
err := handler(conn, req, v)
if err != nil {
HandleWSError(conn, err)
}
case redis.Subscription:
log.Printf("%s: %s %d\n", v.Channel, v.Kind, v.Count)
case error:
log.Printf("error in redis subscription; err:\n%v\n", v)
HandleWSError(conn, v)
default:
// do nothing...
log.Printf("unknown redis subscription event type; %s\n", reflect.TypeOf(v))
}
}
}
}(done, &req, conn)
}
}
答案 0 :(得分:1)
完成服务websocket连接后,进行这些更改以突破读取循环:
维护为此websocket连接创建的Redis连接片段。
完成后取消订阅所有连接。
修改读取循环以在订阅计数为零时返回。
以下是代码:
func wsHandler(w http.ResponseWriter, r *http.Request) {
var upgrader = websocket.Upgrader{
ReadBufferSize: 1024,
WriteBufferSize: 1024,
}
conn, err := upgrader.Upgrade(w, r, nil)
if err != nil {
HandleError(w, err)
return
}
defer conn.Close()
// Keep slice of all connections. Unsubscribe all connections on exit.
var pscs []redis.PubSubConn
defer func() {
for _, psc := range rcs {
psc.Unsubscribe() // unsubscribe with no args unsubs all channels
}
}()
for {
var req WSRequest
err := conn.ReadJSON(&req)
if err != nil {
HandleWSError(conn, err)
return
}
rc := redisPool.Get()
psc := redis.PubSubConn{Conn: rc}
pscs = append(pscs, psc)
if err := psc.PSubscribe(req.chanName); err != nil {
HandleWSError(conn, err)
return
}
go func(req *WSRequest, conn *websocket.Conn) {
defer rc.Close()
for {
switch v := psc.Receive().(type) {
case redis.PMessage:
err := handler(conn, req, v)
if err != nil {
HandleWSError(conn, err)
}
case redis.Subscription:
log.Printf("%s: %s %d\n", v.Channel, v.Kind, v.Count)
if v.Count == 0 {
return
}
case error:
log.Printf("error in redis subscription; err:\n%v\n", v)
HandleWSError(conn, v)
default:
// do nothing...
log.Printf("unknown redis subscription event type; %s\n", reflect.TypeOf(v))
}
}
}(&req, conn)
}
}
问题中的代码和此答案为每个websocket客户端拨打多个Redis连接。更典型和可扩展的方法是跨多个客户端共享单个Redis pubsub连接。鉴于高级描述,典型的方法可能适合您的应用程序,但我仍然不确定您在给出问题中的代码时尝试做什么。