我试图替换Word Online文档中的某些文本但无法使其工作。
' {{test}},[[test]],{test}'结果在
 2,3,3'而不是' 1,2,3'。
第一个文本似乎被处理了两次。
非常感谢任何帮助!
Office.initialize = function(reason) {
function ready() {
var myTags = [
{ "value": "1", "text": "{{test}}" },
{ "value": "2", "text": "[[test]]" },
{ "value": "3", "text": "{test}" }
];
async function FillTag(tag) {
await Word.run(async function(context) {
var options = Word.SearchOptions.newObject(context);
options.matchWildCards = false;
var searchResults = context.document.body.search(tag.text, options);
context.load(searchResults, 'text');
await context.sync();
searchResults.items.forEach(function(item) {
item.insertText(tag.value, Word.InsertLocation.replace);
});
await context.sync();
})
.catch(function(error) {
console.log('Error: ' + JSON.stringify(error));
if (error instanceof OfficeExtension.Error) {
console.log('Debug info: ' + JSON.stringify(error.debugInfo));
}
});
}
async function ProcessArray(myTags) {
myTags.forEach(async function(tag) {
await FillTag(tag);
});
}
ProcessArray(myTags);
}
if (document.readyState !== 'loading') {
ready();
}
else {
document.addEventListener('DOMContentLoaded', ready);
}
};
答案 0 :(得分:2)
在ProcessArray()
函数中,尝试使用forEach
语句替换for...of
语句,如下所示:
async function ProcessArray(myTags) {
for (var tag of myTags) {
await FillTag(tag);
}
}
似乎forEach
语句会触发多个异步调用,而不是实际等待每次FillTag
完成。如上所示,如果您将forEach
语句替换为for...of
,则应获得预期结果。
更新(其他信息重新编码结构):
@DutchDan - 现在您的初始问题已经解决,这是构建代码的更佳方式。
Office.initialize = function () {
$(document).ready(function () {
FindAndReplace();
});
};
async function FindAndReplace() {
var myTags = [
{ "value": "1", "text": "{{test}}" },
{ "value": "2", "text": "[[test]]" },
{ "value": "3", "text": "{test}" }
];
await Word.run(async (context) => {
for (var tag of myTags) {
var options = Word.SearchOptions.newObject(context);
options.matchWildCards = false;
var searchResults = context.document.body.search(tag.text, options);
context.load(searchResults, 'text');
await context.sync();
searchResults.items.forEach(function (item) {
item.insertText(tag.value, Word.InsertLocation.replace);
});
await context.sync();
}
}).catch(errorHandler);
}
注意 :您可以使用脚本实验室(https://aka.ms/getscriptlab)自行快速轻松地尝试此代码段。只需安装Script Lab加载项(免费),然后在导航菜单中选择“导入”,并使用以下Gist URL:https://gist.github.com/kbrandl/b0c9d9ce0dd1ef16d61372cb84636898。
答案 1 :(得分:1)
这是一个调试建议而非答案,但可以在以后编辑。请将Script Lab tool from AppSource安装到Word中。您可以在其中找到的示例代码段之一称为搜索。代码段中的一个功能是basicSearch。我将搜索文本“在线”替换为“{{test}}”,然后用以下行替换了突出显示黄色文本的行:
results.items[i].insertText("1", Word.InsertLocation.replace);
这很好用,所以在简单的场景中,它可以准确地找到并替换“{{test}}”。
请你自己尝试一下,然后逐渐改变方法,使其与你的方法更加相似,看看它在什么时候开始破裂?
修改1/15/18:
@Kim Brandl 的回答可能是最好的,假设你真的只有3个搜索字符串。但是,它在循环中有一个context.sync
。由于每个同步都是到Office主机的往返,因此当输入数量很大和/或加载项在Office Online中运行时(这意味着Office主机是跨越Internet的同一个实例),这可能是一个性能问题机)。
对于阅读此内容且拥有大量输入字符串的人来说,这是一个解决方案,可以保证整个Word.run
中不需要超过3个同步。它还直接攻击您要解决的问题的来源,这是一些找到的范围与其他人的相对位置(具体地,一些在其他范围内)。
我在Word-Add-in-Angular2-StyleChecker中使用的策略是首先加载所有范围,然后使用Range.compareLocationWith方法和LocationRelation枚举来查找所需的相对位置信息。最后,使用每个范围与其他范围的相对位置来确定是否/如何处理它。
这是功能。按照Kim的例子,我将整个片段放在gist中,您可以将其导入Script Lab tool from AppSource。 (参见Kim Brandl的回答中的说明。)
async function FindAndReplace() {
let myTags = [
{ "value": "1", "text": "{{test}}" },
{ "value": "2", "text": "[[test]]" },
{ "value": "3", "text": "{test}" },
{ "value": "4", "text": "bob" },
{ "value": "5", "text": "bobb" },
{ "value": "6", "text": "ssally" },
{ "value": "7", "text": "sally" }
];
let allSearchResults = [];
await Word.run(async (context) => {
for (let tag of myTags) {
let options = Word.SearchOptions.newObject(context);
options.matchWildCards = false;
let searchResults = context.document.body.search(tag.text, options);
searchResults.load('text');
// Store each set of found ranges and the text that should replace
// them together, so we don't have to reconstruct the correlation
// after the context.sync.
let correlatedSearchResult = {
searchHits: searchResults,
replacementString: tag.value
}
allSearchResults.push(correlatedSearchResult);
}
await context.sync();
// Now that we've loaded the found ranges we correlate each to
// its replacement string, and then find each range's location relation
// to every other. For example, 'bob' would be Inside 'xbobx'.
let correlatedFoundRanges = [];
allSearchResults.forEach(function (correlatedSearchResult) {
correlatedSearchResult.searchHits.items.forEach(function (foundRange) {
let correlatedFoundRange = {
range: foundRange,
replacementText: correlatedSearchResult.replacementString,
locationRelations: []
}
correlatedFoundRanges.push(correlatedFoundRange);
});
});
// Two-dimensional loop over the found ranges to find each one's
// location relation with every other range.
for (let i = 0; i < correlatedFoundRanges.length; i++) {
for (let j = 0; j < correlatedFoundRanges.length; j++) {
if (i !== j) // Don't need the range's location relation with itself.
{
let locationRelation = correlatedFoundRanges[i].range.compareLocationWith(correlatedFoundRanges[j].range);
correlatedFoundRanges[i].locationRelations.push(locationRelation);
}
}
}
// It is not necesary to *explicitly* call load() for the
// LocationRelation objects, but a sync is required to load them.
await context.sync();
let nonReplaceableRanges = [];
correlatedFoundRanges.forEach(function (correlatedFoundRange) {
correlatedFoundRange.locationRelations.forEach(function (locationRelation) {
switch (locationRelation.value) {
case "Inside":
case "InsideStart":
case "InsideEnd":
// If the range is contained inside another range,
// blacklist it.
nonReplaceableRanges.push(correlatedFoundRange);
break;
default:
// Leave it off the blacklist, so it will get its
// replacement string.
break;
}
});
});
// Do the replacement, but skip the blacklisted ranges.
correlatedFoundRanges.forEach(function (correlatedFoundRange) {
if (nonReplaceableRanges.indexOf(correlatedFoundRange) === -1) {
correlatedFoundRange.range.insertText(correlatedFoundRange.replacementText, Word.InsertLocation.replace);
}
})
await context.sync();
});
}