我有下面的代码。我想用“NewText”替换文本“Text1”，这是有效的。但是当我将文本“Text1”放在一个不再适用于表格中的“Text1”的表格中时。
我想在所有文件中进行替换。
using (WordprocessingDocument doc = WordprocessingDocument.Open(String.Format("c:\\temp\\filename.docx"), true))
{
var body = doc.MainDocumentPart.Document.Body;
foreach (var para in body.Elements<Paragraph>())
{
foreach (var run in para.Elements<Run>())
{
foreach (var text in run.Elements<Text>())
{
if (text.Text.Contains("##Text1##"))
text.Text = text.Text.Replace("##Text1##", "NewText");
}
}
}
}
答案 0 :(得分：14)
您的代码不起作用，因为表格元素（w:tbl）未包含在内
段落元素（w:p）。有关详细信息，请参阅以下MSDN文章。
Text类（序列化为w:t）通常表示一个Run元素中的文字文本
word文档。因此，您只需搜索所有w:t元素（Text类）并替换您的
如果文本元素（w:t）包含您的标记，则标记：
using (WordprocessingDocument doc = WordprocessingDocument.Open("yourdoc.docx", true))
{
var body = doc.MainDocumentPart.Document.Body;
foreach (var text in body.Descendants<Text>())
{
if (text.Text.Contains("##Text1##"))
{
text.Text = text.Text.Replace("##Text1##", "NewText");
}
}
}
答案 1 :(得分：8)
在各个地方借用其他一些答案，并且必须克服四个主要障碍：
我确信书签，复杂嵌套等高级场景需要对此进行更多修改，但它适用于我到目前为止遇到的基本word文档类型，并且比完全忽略运行对我更有帮助或者在整个文件上使用RegEx，无法定位特定的TableCell或Document部分（针对高级方案）。
示例用法：
var body = document.MainDocumentPart.Document.Body;
ReplaceText(body, replace, with);
代码：
using System;
using System.Collections.Generic;
using System.Linq;
using DocumentFormat.OpenXml;
using DocumentFormat.OpenXml.Packaging;
using DocumentFormat.OpenXml.Wordprocessing;
namespace My.Web.Api.OpenXml
{
public static class WordTools
{
/// <summary>
/// Find/replace within the specified paragraph.
/// </summary>
/// <param name="paragraph"></param>
/// <param name="find"></param>
/// <param name="replaceWith"></param>
public static void ReplaceText(Paragraph paragraph, string find, string replaceWith)
{
var texts = paragraph.Descendants<Text>();
for (int t = 0; t < texts.Count(); t++)
{ // figure out which Text element within the paragraph contains the starting point of the search string
Text txt = texts.ElementAt(t);
for (int c = 0; c < txt.Text.Length; c++)
{
var match = IsMatch(texts, t, c, find);
if (match != null)
{ // now replace the text
string[] lines = replaceWith.Replace(Environment.NewLine, "\r").Split('\n', '\r'); // handle any lone n/r returns, plus newline.
int skip = lines[lines.Length - 1].Length - 1; // will jump to end of the replacement text, it has been processed.
if (c > 0)
lines[0] = txt.Text.Substring(0, c) + lines[0]; // has a prefix
if (match.EndCharIndex + 1 < texts.ElementAt(match.EndElementIndex).Text.Length)
lines[lines.Length - 1] = lines[lines.Length - 1] + texts.ElementAt(match.EndElementIndex).Text.Substring(match.EndCharIndex + 1);
txt.Space = new EnumValue<SpaceProcessingModeValues>(SpaceProcessingModeValues.Preserve); // in case your value starts/ends with whitespace
txt.Text = lines[0];
// remove any extra texts.
for (int i = t + 1; i <= match.EndElementIndex; i++)
{
texts.ElementAt(i).Text = string.Empty; // clear the text
}
// if 'with' contained line breaks we need to add breaks back...
if (lines.Count() > 1)
{
OpenXmlElement currEl = txt;
Break br;
// append more lines
var run = txt.Parent as Run;
for (int i = 1; i < lines.Count(); i++)
{
br = new Break();
run.InsertAfter<Break>(br, currEl);
currEl = br;
txt = new Text(lines[i]);
run.InsertAfter<Text>(txt, currEl);
t++; // skip to this next text element
currEl = txt;
}
c = skip; // new line
}
else
{ // continue to process same line
c += skip;
}
}
}
}
}
/// <summary>
/// Determine if the texts (starting at element t, char c) exactly contain the find text
/// </summary>
/// <param name="texts"></param>
/// <param name="t"></param>
/// <param name="c"></param>
/// <param name="find"></param>
/// <returns>null or the result info</returns>
static Match IsMatch(IEnumerable<Text> texts, int t, int c, string find)
{
int ix = 0;
for (int i = t; i < texts.Count(); i++)
{
for (int j = c; j < texts.ElementAt(i).Text.Length; j++)
{
if (find[ix] != texts.ElementAt(i).Text[j])
{
return null; // element mismatch
}
ix++; // match; go to next character
if (ix == find.Length)
return new Match() { EndElementIndex = i, EndCharIndex = j }; // full match with no issues
}
c = 0; // reset char index for next text element
}
return null; // ran out of text, not a string match
}
/// <summary>
/// Defines a match result
/// </summary>
class Match
{
/// <summary>
/// Last matching element index containing part of the search text
/// </summary>
public int EndElementIndex { get; set; }
/// <summary>
/// Last matching char index of the search text in last matching element
/// </summary>
public int EndCharIndex { get; set; }
}
} // class
} // namespace
public static class OpenXmlTools
{
// filters control characters but allows only properly-formed surrogate sequences
private static Regex _invalidXMLChars = new Regex(
@"(?<![\uD800-\uDBFF])[\uDC00-\uDFFF]|[\uD800-\uDBFF](?![\uDC00-\uDFFF])|[\x00-\x08\x0B\x0C\x0E-\x1F\x7F-\x9F\uFEFF\uFFFE\uFFFF]",
RegexOptions.Compiled);
/// <summary>
/// removes any unusual unicode characters that can't be encoded into XML which give exception on save
/// </summary>
public static string RemoveInvalidXMLChars(string text)
{
if (string.IsNullOrEmpty(text)) return "";
return _invalidXMLChars.Replace(text, "");
}
}
答案 2 :(得分：3)
也许这个解决方案更容易
using (WordprocessingDocument wordDoc = WordprocessingDocument.Open(document, true))
{
string docText = null;
//1. Copy all the file into a string
using (StreamReader sr = new StreamReader(wordDoc.MainDocumentPart.GetStream()))
docText = sr.ReadToEnd();
//2. Use regular expression to replace all text
Regex regexText = new Regex(find);
docText = regexText.Replace(docText, replace);
//3. Write the changed string into the file again
using (StreamWriter sw = new StreamWriter(wordDoc.MainDocumentPart.GetStream(FileMode.Create)))
sw.Write(docText);