Question

在SSMS中，我有一个包含x，y和z列的表。该表描述了三维景观的外缘。

对于这些要点中的每一点，我想创建两个新行。

第1行（水平转换）

如果行位于x范围的左侧一半，那么我想添加一个 x 值为零的行，我想保留相同的y和z值
如果该行位于x范围的右侧一半，那么我想添加一个 x 值为max（x）的行，我想保留相同的y和z值

第2行（垂直转换）

如果行位于y范围的底部一半，那么我想添加一个 y 值为0的行，我想保留相同的x和z值
如果行位于y范围的顶部一半，那么我想添加一个 y 值为max（y）的行，我想保留相同的x和z值

样本数据

y           x            z
549963.253  293753.256  -1757.842
549677.683  297976.459  -1620.247
558873.083  309630.362  -1577.014
551514.017  285295.081  -1658.569
555753.949  304347.046  -1492.961
536874.470  298448.332  -1558.507
552574.391  297353.342  -1546.272
546114.102  314972.371  -1565.327
531771.077  292503.656  -1407.629
556505.724  306902.763  -1538.788
549090.490  288432.773  -1371.135
548953.512  302602.260  -1497.929
548690.957  305676.277  -1487.923
562452.487  307043.899  -1417.623
544858.390  311193.462  -1482.092
548554.806  297235.212  -1367.308
553771.112  305062.276  -1363.437
546734.711  283794.627  -1474.116
564066.496  307061.364  -1385.391
564559.510  303185.772  -1517.316
545010.760  305789.647  -1374.378
551738.567  304001.895  -1430.129
564864.830  305701.078  -1477.312
571958.715  301258.917  -1373.429
558356.397  291184.015  -1450.972
570675.003  300697.550  -1372.930
565582.654  311963.297  -1351.212
561914.940  292780.756  -1357.631
557361.304  295066.815  -1451.466
565150.027  283631.470  -1265.197
576099.475  280598.922  -1270.946
563291.031  298065.163  -1493.635
564513.518  297643.693  -1482.868
565473.258  300830.589  -1292.136
551821.588  296706.306  -1336.422
578457.061  290637.947  -1316.241
568051.844  295262.721  -1264.061
560403.936  292078.795  -1358.460
580655.446  289384.664  -1344.182
567051.307  303542.217  -1262.574
586391.245  298296.507  -1307.636
563443.629  294610.675  -1369.074
573287.477  287207.832  -1421.306
570396.315  286699.258  -1260.884
569138.520  299396.374  -1404.514
558212.414  290440.978  -1266.421
568117.293  302236.377  -1328.212
575731.212  286185.554  -1408.601
570917.003  288588.953  -1471.324
581951.944  301935.116  -1428.110
576289.570  287879.973  -1384.389
579719.593  298122.950  -1367.387
578786.688  296023.543  -1312.228
583767.111  307032.486  -1280.412
588382.842  297357.328  -1281.912
584809.964  295886.098  -1335.179
586010.252  292049.677  -1323.906
580153.419  289230.973  -1323.889
605095.221  305602.448  -1357.968
594649.250  293677.044  -1355.983
597170.092  313305.495  -1344.910
594051.634  285127.937  -1213.801
584710.587  299341.755  -1256.289
595733.382  280755.433  -1206.703
590237.055  307659.289  -1201.313
585845.543  299665.307  -1324.558
595060.226  298845.650  -1251.863
586105.384  299610.237  -1235.170
596660.231  288586.487  -1169.211
592859.509  298351.276  -1198.438
602007.608  283748.480  -1329.079
591558.062  293431.407  -1202.938
600133.990  294958.829  -1256.143
610423.996  292256.291  -1233.516
600825.888  302732.720  -1148.829
594207.291  289864.311  -1217.495
592249.657  287346.842  -1166.952
599140.528  313087.065  -1154.344
601740.225  298190.310  -1186.768

Answer 1

上半部分不清楚

这是横向转换

  declare @minX money = ( select min([StartingPrice]) FROM [Test].[dbo].[Auction]  )
  declare @maxX money = ( select max([StartingPrice]) FROM [Test].[dbo].[Auction]  )
  declare @avgX money = ( (@minX + @maxX) / 2  )

  select @minX 
  select @maxX 
  select @avgX 

  select [AuctionID], [StartingPrice] from [Test].[dbo].[Auction]
  union all
  select [AuctionID], 0 from [Test].[dbo].[Auction] where [StartingPrice]     <  @avgX 
  union all
  select [AuctionID], @maxX from [Test].[dbo].[Auction] where [StartingPrice] >= @avgX

Answer 2

以下代码显示了一种方法。它通过收集最小值和最大值的数据（或从适当的索引中获取它们），计算中心值，然后使用调整后的x和y值生成要插入的行

正如原始问题所暗示的那样，将跳过值与范围中心值匹配的行。如果这不正确，则应删除where子句，并根据需要调整case个表达式，以替换正确的值。

insert 语句留给读者练习。

-- Sample data.
declare @Samples as Table ( SampleId Int Identity,
  X Decimal(10,4), Y Decimal(10,4), Z Decimal(10,4) );
insert into @Samples ( X, Y, Z ) values
  ( -5, 1, 22 ), ( 0, 10, 18 ), ( 5, 20, -16 );
select * from @Samples;

-- Demonstrate getting the minima, maxima and center values.
with
  Step1 as (
    select Min( X ) as MinX, Max( X ) as MaxX, Min( Y ) as MinY, Max( Y ) as MaxY
      from @Samples ),
  Step2 as (
    select MinX, MaxX, ( MinX + MaxX ) / 2.0 as CenterX, MinY, MaxY, ( MinY + MaxY ) / 2.0 as CenterY
      from Step1 )
  select * from Step2;

-- Get the rows to be inserted.
with
  Step1 as (
    select Min( X ) as MinX, Max( X ) as MaxX, Min( Y ) as MinY, Max( Y ) as MaxY
      from @Samples ),
  Step2 as (
    select MinX, MaxX, ( MinX + MaxX ) / 2.0 as CenterX, MinY, MaxY, ( MinY + MaxY ) / 2.0 as CenterY
      from Step1 )
  select S.SampleId, case when X < CenterX then 0 else MaxX end as X, Y, Z, 'NewX' as RowType
    from @Samples as S cross join
      Step2 as S2
    where S.X != S2.CenterX
  union all
  select S.SampleId, X, case when Y < CenterY then 0 else MaxY end, Z, 'NewY'
    from @Samples as S cross join
      Step2 as S2
    where S.Y != S2.CenterY;

数据扩展数据点

2 个答案: