Question

我有这个程序来识别URL在消息中的位置并且只在URL中保留字符串，但它只是随机跳过值而我不知道为什么。这是我的代码和调试控制台。

function DeleteNonURL(sep, URL)
{
    var _Pos = new Number;
    URL = URL.split(sep);
    for (var i = 0; i < URL.length; i++)//deletes non-url substrings
    {
    Debug.Trace("Msg: "+URL + " i: "+i + " _Pos: "+_Pos + " Current Substring: "+URL[i]);
        _Pos = URL[i].indexOf('.com');
        if(_Pos == -1)
        {
            _Pos = URL[i].indexOf('.net');
            if(_Pos == -1)
            {
                _Pos = URL[i].indexOf('.org');
                if(_Pos == -1)
                {
                    _Pos = URL[i].indexOf('.info');
                    if(_Pos == -1) //No URL in this substr
                    {
                        URL.splice(i, 1); //deleted.
                    }
                }
            }
        }
    }
    Debug.Trace(URL);
}

Debug:
Msg: Hey,dude,look,at,this,amazon.com,what,is,it? i: 0 _Pos: 0 Current Substring: Hey

Msg: dude,look,at,this,amazon.com,what,is,it? i: 1 _Pos: -1 Current Substring: look

Msg: dude,at,this,amazon.com,what,is,it? i: 2 _Pos: -1 Current Substring: this

Msg: dude,at,amazon.com,what,is,it? i: 3 _Pos: -1 Current Substring: what

Msg: dude,at,amazon.com,is,it? i: 4 _Pos: -1 Current Substring: it?

dude,at,amazon.com,is

Answer 1

正如评论中所指出的，当突变导致数组重新编制索引时，这是一个非常普遍的变异问题，即你正在迭代的数组。

最终，您似乎想要检查以其中一个TLD结尾的子字符串。这可以更简单地完成。

＆＃13;

const re = /\.(?:com|net|org|info)$/;

function test(sep, URL) {
    return URL.split(sep).find(s => re.test(s));
}

const a = "http://example.com/foo/bar";
const b = "foo/bar/baz";

console.log("TLD part", test('/', a));
console.log("TLD part", test('/', b));

＆＃13;

对于循环跳过值

1 个答案: