Question

在这个for循环中cin.get（）;每隔一段时间都会被跳过。我不知道为什么会被跳过。任何帮助将不胜感激。

代码：

for(Pointer = StartPointer; Pointer < EndPointer; Pointer += MemInfo.RegionSize)
{

    VirtualQueryEx(hProc, (LPCVOID)(Pointer), &MemInfo, sizeof(MemInfo));
    cout << "MemInfo AllocationBase: " << MemInfo.AllocationBase << endl;
    cout << "MemInfo AllocationProtect: " << MemInfo.AllocationProtect << endl;
    cout << "MemInfo BaseAddress: " << MemInfo.BaseAddress << endl;
    cout << "MemInfo Protect: " << MemInfo.Protect << endl;
    cout << "MemInfo RegoinSize: " << MemInfo.RegionSize << endl;
    cout << "MemInfo State: " << MemInfo.State << endl;
    cout << "MemInfo Type: " << MemInfo.Type << endl;
    cout << "MemInfo Size: " << sizeof(MemInfo) << endl;
    cout << "Starter pointer is: " << StartPointer << endl;
    cin.get();
}

cin.get（）;

之间的输出示例

MemInfo AllocationBase: 00000000
MemInfo AllocationProtect: 0
MemInfo BaseAddress: 00000000
MemInfo Protect: 1
MemInfo RegoinSize: 65536
MemInfo State: 65536
MemInfo Type: 0
MemInfo Size: 28
Starter pointer is: 0
MemInfo AllocationBase: 00010000
MemInfo AllocationProtect: 4
MemInfo BaseAddress: 00010000
MemInfo Protect: 4
MemInfo RegoinSize: 65536
MemInfo State: 4096
MemInfo Type: 262144
MemInfo Size: 28
Starter pointer is: 0

Answer 1

cin.get()未获得您键入的'\n'〜

尝试使用，

string str;
getline(cin, str)

而不是cin.get()

或在getchar()

之后添加cin.get()

Answer 2

因为你在Windows上：

#include <conio.h>

// .. your other stuff

_getch();

cin.get()将抓住输入缓冲区中的任何内容（如果你按下输入，空格，或者几乎在键盘上呼吸，它会有一些东西），或EOF如果什么都没有，所以它总会回来。

C ++ for循环跳过cin.get（）

2 个答案: