我正在寻找如何连接到mysql数据库的最简单的解决方案,例如,检索和更新数据。我试过做我的研究,但我找不到任何真正的东西。我的意思是,我敢打赌这是一个简单的方法。我之前使用过PHP,我认为使用C#连接到数据库相对容易。
有人可以给我看一下如何连接mysql数据库的示例代码吗?另外,如何检索和更新数据?拜托,谢谢!
答案 0 :(得分:0)
我不清楚你的意思,但我已经使用了www表格。
从youtube开始关注this教程系列。
总之;您将创建www表单并将所需数据发送到PHP代码。有了PHP代码的答案,你可以完成你的任务。我将尝试提供一个例子。
Unity C#登录脚本
using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.UI;
using UnityEngine.SceneManagement;
public class LoginScript : MonoBehaviour {
public GameObject inputUsernameText;
public GameObject inputPasswordText;
public string inputUsername;
public string inputPassword;
public string userUsername;
public string userPassword;
public string[] userDataArray;
string loginURL ="YOUR LOGIN PHP CODE URL HERE" ;
public bool isLoginButtonPressed;
void Awake() {
DontDestroyOnLoad(transform.gameObject);
}
// Use this for initialization
void Start () {
}
// Update is called once per frame
void Update () {
if (isLoginButtonPressed)
{
StartCoroutine(loginToDB (inputUsername, inputPassword));
isLoginButtonPressed = false;
}
}
IEnumerator loginToDB(string username, string password)
{
WWWForm form = new WWWForm();
form.AddField("usernamePost", username);
form.AddField("passwordPost", password);
WWW www = new WWW (loginURL, form);
yield return www;
//Debug.Log (www.text);
userDataArray = userEkipIDString.Split ('|');
userUsername = userDataArray [0];
userPassword = userDataArray [1];
isLoginButtonPressed = false;
SceneManager.LoadScene("MainMenuScene", LoadSceneMode.Single);
}
public void loginButtonPressedFunc()
{
inputUsername = inputUsernameText.GetComponent<Text> ().text.ToString ();
inputPassword = inputPasswordText.GetComponent<Text> ().text.ToString ();
isLoginButtonPressed = true;
}
}
这个脚本的作用是,它从Unity的输入字段中获取用户名和密码并将其发送到php代码。如果用户名和密码正确,则会加载另一个场景。
PHP代码
<?php
$servername = "YOUR HOST NAME ex:localhost";
$username = "YOUR DB USER NAME";
$password = "YOUR DB PASSWORD";
$dbName = "YOUR DB NAME";
$user_username = $_POST["usernamePost"];
$user_password = $_POST["passwordPost"];
//Make Connection
$conn = mysqli_connect($servername,$username,$password,$dbName);
//Check Connection
if(!$conn)
{
die("Connection Failed. " . mysqli_connect_error());
}
//else echo ("Connection Success.");
$sql ="Select user, pass from "YOUR TABLE NAME" where user = '".$user_username."' "; //You can write your own query here
$result = mysqli_query($conn,$sql);
//Get the result and confirm login
if(mysqli_num_rows($result)>0)
{
//show data for each row
while($row = mysqli_fetch_assoc($result))
{
if($row['pass'] == $user_password)
{
//echo "Login Success";
echo "".$row['user']."|".$row['pass']."" ;
}
else
{
echo "Wrong Password";
}
}
}
else
{
echo "User not found";
}
?>
您可以调整此逻辑以插入,更新和删除
希望这会有所帮助。干杯!