Question

这对您来说似乎非常基础，我想我知道我的代码有什么问题，我似乎无法弄清楚如何修复。基本上，我正在建立一个非常简单的刽子手游戏，我想让用户每次猜错信都会失去生命。这是代码：

import random
word_choice = ["list", "microsoft", "cars", "philosophy", "mother", "powder", "star", "baby", "elephant"]
guessed_letters = []
right_guessed_letters = []




def user_turn(c):
    lives = 10
    while True:
        guess = input("\nGuess a letter or a word: ")
        guessed_letters.append(guess)
        print ("\n")
        if lives != 0 and guess != comp_choice:
            if guess in comp_choice:
                right_guessed_letters.append(guess)
                for i in comp_choice:
                    if i in right_guessed_letters:
                        print (i, end= ' ')
                    else:
                        print ('-', end = ' ')
            else:
                lose_life(lives)
            continue
        elif guess == comp_choice:
            print ("Good job, you guessed the word correctly!")
            break
        elif  lives == 0:
            print ("You lost, your lives are all depleated...")
            break

def lose_life(l):
    l -= 1
    print (f'Wrong letter, you have {l} lives remaining')
    print (f"The letters you already guessed are {guessed_letters}")



comp_choice = random.choice(word_choice)
word = '-' * len(comp_choice)
print (f"Your word is : {word} long.")


user_turn(comp_choice)

基本上，我的问题是用户只能失去一条生命。事实上，我希望每次调用lose_life，用户都会失去生命，所以他的生命每次都减少一次，然而变量生命在功能完成后立即获得它的原始值。因此，每次调用该函数时，用户都处于九次生命中。这是输出：

microsoft
Your word is : --------- long.

Guess a letter or a word: d


Wrong letter, you have 9 lives remaining
The letters you already guessed are ['d']

Guess a letter or a word: e


Wrong letter, you have 9 lives remaining
The letters you already guessed are ['d', 'e']

Guess a letter or a word:

无论如何，如果你能提供帮助，我们将非常感激！

Answer 1

你的lose_life函数没有返回任何内容，所以它实际上只是打印两个语句。

如果您在return l函数的末尾添加了lose_life，并将else语句中的lose_life(lives)更改为lives = lose_life(lives)，则它现在可以正常工作。

如果这看起来很麻烦并且你有冒险的感觉，你可以考虑改用Classes：

class Live(object):
    def __init__(self, value=10):
        self.value = value
    def __str__(self):
        return str(self.value)
    def __repr__(self):
        return self.__str__()
    def lose(self):
        self.value -= 1
        print(f'Wrong letter, you have {self.value} lives remaining')
        print(f"The letters you already guessed are {guessed_letters}")
    def gain(self):
        self.value += 1
        # insert your own print messages if you wish.

请注意，我不建议为此用例执行此操作（KISS主要适用），但对于需要自己的属性和功能的对象的更复杂项目，类非常适用于此目的。

每次循环滚动时如何使变量减1？

1 个答案: