Question

我试图制作一个程序，将莫尔斯代码转换为文本，但它返回代码0xC0000005。我已尽可能多地搜索但我无法找到解决方案。这是我写的代码：

#include <iostream>
#include <cstdlib>
#include <cstring>

using namespace std;

int find_position(string toFind){
    string codes[26]={ ".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.." };
    for(int a=0;a<26;a++){
        if(codes[a]==toFind){
            return a;
        }
    }
}

int main(){
    cout << "Enter the code(seprate with space)";
    char to_translate[1000];
    cin.getline(to_translate,1000);
    int c,code;
    string words[1000];
    for(int a=0;a<sizeof(to_translate);a++){
        if(to_translate[a]!=' '){
            words[c] += to_translate[a];
        }else{c++;}
    }
    string words2[sizeof(words)];
    c=0;
    for(int a=0;a<sizeof(words);a++){
        if(words[a]=="/"){
            c++;
        } else{
            words2[c] += (char) (find_position(words[a])+64);
        }
    }
    cout << words2;
    return 0;
}

Answer 1

你有一行文字，用"/"排除形成莫尔斯词，用" "形成莫尔斯字母。

std::getline接受deliminator参数，可让您轻松将文本拆分为相关细分。

#include <iostream>
#include <sstream>
#include <string>
#include <map>

int main()
{   
    std::map<std::string, char> morse = { { ".-", 'A' }, }; // etc

    std::cout << "Enter the code(separate letters with space and words with slash)";
    std::string line;
    std::getline(std::cin, line);
    std::stringstream line_stream(line);
    for (std::string morse_word; std::getline(line_stream, morse_word, '\\');)
    {
        std::stringstream word_stream(morse_word);
        std::stringstream word;
        for (std::string letter; std::getline(word_stream, letter, ' ');)
        {
            word.put(morse[letter]);
        }
        std::cout << word.str();
    }
    return 0;
}

如何在此C ++代码中找到错误？

1 个答案: