Question

我有这个脚本：

 #!/usr/local/bin/gawk -f

BEGIN{
    FS="=|,"
    PROCINFO["sorted_in"]="@ind_num_asc";
    printf "\n"
    printf "%-7s %s", "Count", "Amount"
    printf "\n"
    OFS="\t"
}
/phrase/{
    for (i=4; i 3<= 5; i++ )
        if ($i != "") a[$i]++
}

END{
    for (i in a) {print a[i], i; tot++}
    printf "\n"
    printf " ***** %s total wins *****", tot
    printf "\n"
}

产生此输出：

Count   Amount
1       20
1       22
1       29
1       37
1       38
1       45
1       46
2       80
1       99
1       800

 ***** 10 total unique amounts *****

我想打印出第二个字段的总和，但请注意计数数量从1到很多不等。 for循环中是否应该有一个while循环来总结计数或在END的脚本结尾处进行数学计算？

感谢您提供的任何提示！

gawk用

提取的示例数据

gawk -F"=|," '/phrase/ {print $4}' file
80
800
20
46
38
45
99
80
29
22
37

解析前的数据示例：

.\phrase(100): [LOG] API context: context=3, amount=80
.\phrase(100): [LOG] API context: context=3, amount=800
.\phrase(100): [LOG] API context: context=3, amount=20
.\phrase(100): [LOG] API context: context=3, amount=46
.\phrase(100): [LOG] API context: context=3, amount=38
.\phrase(100): [LOG] API context: context=3, amount=45
.\phrase(100): [LOG] API context: context=3, amount=99
.\phrase(100): [LOG] API context: context=3, amount=80
.\phrase(100): [LOG] API context: context=3, amount=29
.\phrase(100): [LOG] API context: context=3, amount=22
.\phrase(100): [LOG] API context: context=3, amount=37

预期结果：

Count   Amount
1       20
1       22
1       29
1       37
1       38
1       45
1       46
2       80
1       99
1       800

***** 10 total unique amounts *****
***** 1296 sum totals         *****

Answer 1

关注awk可能对您有帮助。

awk -F'=' '{a[$NF]++;sum+=$NF} END{print "Count   Amount";for(i in a){print a[i]"\t"i;};print "***** " length(a),"total unique amounts *****" RS "***** " sum "sum totals         *****"}'  Input_file

输出如下。

Count   Amount
2       80
1       45
1       37
1       46
1       29
1       38
1       20
1       22
1       800
1       99
***** 10 total unique amounts *****
***** 1296sum totals         *****

Answer 2

基本上它应该是：

awk -F= '{a[$NF]++;t+=$NF} # You can calculate the total here
         END{
             for(i in a) print a[i], i
             printf "%s uniq\n", length(a)
             printf "%s total\n", t
         }' a.txt

为简洁起见，我省略了排序和打印标题。

awk sum for for循环

2 个答案: