在互联网上搜索,我无法解决这个问题。
我有一个带定价计划开关的定价部分。逻辑本身工作正常,但是CSS复选框切换本身并不是从左向右切换。
我认为它与CSS本身或我用JS选择元素的方式有关。我还阅读了一些关于SO的话题,他们说这是WordPress的复选框问题,遗憾的是没有找到答案。
问题
Link to Dropbox of me demonstrating the issue on iPhone
window.onload = function() {
var e = document.getElementById("firstPlan"),
d = document.getElementById("secondPlan"),
t = document.getElementById("switcher_iOS"),
m = document.getElementById("firstPlan_box"),
y = document.getElementById("secondPlan_box");
if (document.getElementById("switcher_iOS") == null) {
var node = document.createElement("input");
node.id = "switcher_iOS";
node.type = "checkbox";
node.className = "toggle_iOS--check";
var elm = document.getElementsByClassName('toggle_iOS')[0];
elm.insertBefore(node, elm.firstChild)
t = document.getElementById("switcher_iOS");
}
e.addEventListener("click", function() {
t.checked = false;
e.classList.add("togglePricing--is-active");
d.classList.remove("togglePricing--is-active");
m.classList.remove("hide");
y.classList.add("hide");
});
d.addEventListener("click", function() {
t.checked = true;
d.classList.add("togglePricing--is-active");
e.classList.remove("togglePricing--is-active");
m.classList.add("hide");
y.classList.remove("hide");
});
t.addEventListener("click", function() {
d.classList.toggle("togglePricing--is-active");
e.classList.toggle("togglePricing--is-active");
m.classList.toggle("hide");
y.classList.toggle("hide");
t.checked = !t.checked;
})
}
/* Toggle */
#switcher_iOS {
width: 100%;
}
.toggle_iOS,
.togglePricing {
display: inline-block;
vertical-align: middle;
margin: 10px;
}
.togglePricing {
color: #ccc9c9;
cursor: pointer;
transition: .1s;
font-weight: bold;
font-size: 17px;
}
.togglePricing--is-active {
color: #181818;
}
.toggle_iOS {
position: relative;
width: 58px;
height: 28px;
border-radius: 100px;
background-color: #1D8BF1;
overflow: hidden;
box-shadow: inset 0 0 2px 1px rgba(0, 0, 0, 0.05);
}
.toggle_iOS--check {
position: absolute;
display: block;
cursor: pointer;
top: 0;
left: 0;
width: 100%;
height: 100%;
opacity: 0;
z-index: 6;
}
.toggle_iOS--check:checked~.toggle_iOS--switch {
right: 2px;
left: 57.5%;
transition: 0.15s cubic-bezier(0.785, 0.135, 0.15, 0.86);
transition-property: left, right;
transition-delay: .01s, 0s;
}
.toggle_iOS--switch {
position: absolute;
left: 2px;
top: 2px;
cursor: pointer;
bottom: 2px;
right: 57.5%;
background-color: #fff;
border-radius: 36px;
z-index: 1;
transition: 0.15s cubic-bezier(0.785, 0.135, 0.15, 0.86);
transition-property: left, right;
transition-delay: 0s, .01s;
box-shadow: 0 1px 2px rgba(0, 0, 0, 0.2);
}
<label class="togglePricing togglePricing--is-active" id="firstPlan">Payment Plan</label>
<div class="toggle_iOS">
<label for="switcher_iOS"><input type="checkbox" onclick="void(0);" id="switcher_iOS" class="toggle_iOS--check" checked></label><b onclick="void(0);" class="toggle_iOS--switch"></b>
</div>
<label class="togglePricing" id="secondPlan">One Payment</label>
答案 0 :(得分:0)
我已经简化了你的css,为了使它能够工作,你必须从点击事件的复选框中删除你的JS重置复选框的状态,例如
t.checked = !t.checked;
var t = document.getElementById("switcher_iOS");
t.addEventListener("click", function(){
console.log("i am", this.checked);
})
.toggle_iOS{
position: relative;
width: 58px;
height: 28px;
border-radius: 100px;
background-color: #1D8BF1;
overflow: hidden;
box-shadow: inset 0 0 2px 1px rgba(0,0,0,0.05);
}
.toggle_iOS--switch{
position: absolute;
left: 2px;
top: 2px;
cursor: pointer;
bottom: 2px;
right: 57.5%;
background-color: #fff;
border-radius: 36px;
z-index: 1;
transition: 0.15s cubic-bezier(0.785,0.135,0.15,0.86);
transition-property: left,right;
transition-delay: 0s,.01s;
box-shadow: 0 1px 2px rgba(0,0,0,0.2);
}
[type=checkbox]:checked + .toggle_iOS--switch{
left: 57.5%;
right: 2px;
}
.toggle_iOS [type=checkbox]{
position: absolute;
display: block;
cursor: pointer;
top: 0;
left: 0;
width: 100%;
height: 100%;
opacity: 0;
z-index: 6;
}
<div class="toggle_iOS">
<input type="checkbox" id="switcher_iOS">
<div class="toggle_iOS--switch"></div>
</div>