我正在制作一个简单的连续3个益智游戏,我理解的逻辑,但我试图创建我的网格。
我想要做的是在点击蓝色方块时将蓝色瓷砖的背景颜色更改为白色,如果再次单击相同的瓷砖,则将颜色还原为蓝色。我是用纯JavaScript做的。
我的问题:我希望能够根据需要更改颜色,而我目前仅限于更改蓝色 - >白色,然后是白色 - >蓝色没有进一步的变化。这将使用户坚持他们的第三选择,基本上。
我可以进行哪些更改以防止颜色变化在x次点击后停止?
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Grid</title>
<style>
#blueTile {
background-color:blue;
}
td{
text-align: center;
border: 1px solid black;
padding: 3px;
height:50px;
width:50px;
}
table {
border-collapse: collapse;
}
</style>
</head>
body>
<script>
//6x6 array
var solutionArray = new Array(6);
solutionArray[0] = new Array(6);
solutionArray[1] = new Array(6);
solutionArray[2] = new Array(6);
solutionArray[3] = new Array(6);
solutionArray[4] = new Array(6);
solutionArray[5] = new Array(6);
var tile = {};
var blue = tile.colour = "blue";
var white = tile.colour = "white";
var grey = tile.colour = "grey";
solutionArray[0][0]=blue;
solutionArray[0][1]=white;
solutionArray[0][2]=blue;
solutionArray[0][3]=blue;
solutionArray[0][4]=white;
solutionArray[0][5]=blue;
solutionArray[1][0]=white;
solutionArray[1][1]=blue;
solutionArray[1][2]=white;
solutionArray[1][3]=blue;
solutionArray[1][4]=blue;
solutionArray[1][5]=white;
solutionArray[2][0]=blue;
solutionArray[2][1]=white;
solutionArray[2][2]=blue;
solutionArray[2][3]=white;
solutionArray[2][4]=white;
solutionArray[2][5]=blue;
solutionArray[3][0]=white;
solutionArray[3][1]=blue;
solutionArray[3][2]=white;
solutionArray[3][3]=white;
solutionArray[3][4]=blue;
solutionArray[3][5]=blue;
solutionArray[4][0]=blue;
solutionArray[4][1]=blue;
solutionArray[4][2]=white;
solutionArray[4][3]=blue;
solutionArray[4][4]=white;
solutionArray[4][5]=white;
solutionArray[5][0]=blue;
solutionArray[5][1]=white;
solutionArray[5][2]=blue;
solutionArray[5][3]=white;
solutionArray[5][4]=blue;
solutionArray[5][5]=white;
var x = document.createElement("TABLE");
x.setAttribute("id", "gridTable");
document.body.appendChild(x);
for(i=0;i<6;i++)
{
//output the row tag
var y = document.createElement("TR");
y.setAttribute("id", "row"+i);
document.getElementById("gridTable").appendChild(y)
for(j=0;j<solutionArray.length;j++)
{
///output the td tag
var z = document.createElement("TD");
if(solutionArray[i][j] == blue){
z.setAttribute("id", "blueTile");
}
else if (solutionArray[i][j] == white){
z.setAttribute("id", "whiteTile");
}
var t = document.createTextNode(solutionArray[i][j]);
z.appendChild(t);
document.getElementById("row"+i).appendChild(z);
}
}
var blueClick = document.getElementById("blueTile");
blueClick.addEventListener("click", switchColor);
function switchColor(){
blueClick.style.backgroundColor = "white";
blueClick.addEventListener("click", switchBack);
}
function switchBack(){
blueClick.style.backgroundColor = "blue";
blueClick.addEventListener("click", switchColor);
}
</script>
</body>
</html>
答案 0 :(得分:0)
你可以这样做。
//6x6 array
var solutionArray = new Array(6);
solutionArray[0] = new Array(6);
solutionArray[1] = new Array(6);
solutionArray[2] = new Array(6);
solutionArray[3] = new Array(6);
solutionArray[4] = new Array(6);
solutionArray[5] = new Array(6);
var tile = {};
var z = "";
var blue = tile.colour = "blue";
var white = tile.colour = "white";
var grey = tile.colour = "grey";
solutionArray[0][0] = blue;
solutionArray[0][1] = white;
solutionArray[0][2] = blue;
solutionArray[0][3] = blue;
solutionArray[0][4] = white;
solutionArray[0][5] = blue;
solutionArray[1][0] = white;
solutionArray[1][1] = blue;
solutionArray[1][2] = white;
solutionArray[1][3] = blue;
solutionArray[1][4] = blue;
solutionArray[1][5] = white;
solutionArray[2][0] = blue;
solutionArray[2][1] = white;
solutionArray[2][2] = blue;
solutionArray[2][3] = white;
solutionArray[2][4] = white;
solutionArray[2][5] = blue;
solutionArray[3][0] = white;
solutionArray[3][1] = blue;
solutionArray[3][2] = white;
solutionArray[3][3] = white;
solutionArray[3][4] = blue;
solutionArray[3][5] = blue;
solutionArray[4][0] = blue;
solutionArray[4][1] = blue;
solutionArray[4][2] = white;
solutionArray[4][3] = blue;
solutionArray[4][4] = white;
solutionArray[4][5] = white;
solutionArray[5][0] = blue;
solutionArray[5][1] = white;
solutionArray[5][2] = blue;
solutionArray[5][3] = white;
solutionArray[5][4] = blue;
solutionArray[5][5] = white;
var x = document.createElement("TABLE");
x.setAttribute("id", "gridTable");
document.body.appendChild(x);
for (i = 0; i < 6; i++) {
//output the row tag
var y = document.createElement("TR");
y.setAttribute("id", "row" + i);
document.getElementById("gridTable").appendChild(y)
for (j = 0; j < solutionArray.length; j++) {
///output the td tag
var z = document.createElement("TD");
if (solutionArray[i][j] == blue) {
z.setAttribute("class", "blueTile tile blue");
} else if (solutionArray[i][j] == white) {
z.setAttribute("class", "whiteTile tile");
}
var t = document.createTextNode(solutionArray[i][j]);
z.appendChild(t);
document.getElementById("row" + i).appendChild(z);
}
}
document.querySelector("#gridTable").addEventListener("click", function(event) {
if (event.target.tagName === "TD" && event.target.classList.contains("blueTile")) {
event.target.classList.toggle("blue");
}
});
&#13;
.blue {
background-color: blue;
}
td {
text-align: center;
border: 1px solid black;
padding: 3px;
height: 50px;
width: 50px;
}
table {
border-collapse: collapse;
}
.tile {
cursor: pointer;
}
.whiteTile {
-webkit-touch-callout: none;
-webkit-user-select: none;
-khtml-user-select: none;
-moz-user-select: none;
-ms-user-select: none;
user-select: none;
cursor: default;
}
&#13;
答案 1 :(得分:0)
您可能想要改变切换方式。不要使用2个单独的函数,只需对单击处理程序执行以下操作,无需单击任何图块。
function switchColor(e){
var curColor = this.style.backgroundColor;
if(curColor === "white"){
this.style.backgroundColor = "blue";
}
else{
this.style.backgroundColor = "white";
}
}
此外,ID应该是元素的唯一。您在示例中使用它们就像css类一样。这是一个实现它的小提琴。 https://jsfiddle.net/6su0b0w8/