熊猫分裂角色并删除尾随值

Question

我正在尝试删除在保留第一个值时用'['标识的残留数据。

import pandas as pd
df=pd.DataFrame({'foo':['a','b[b7','c']})
print(df)

成为：

0 a
1 b[b7
2 c

想要

0 a
1 b
2 c

有什么建议吗？

Answer 1

df.foo=df.foo.str[0]
df
Out[212]: 
  foo
0   a
1   b
2   c

Answer 2

我认为您正在寻找str.split + str[0] -

df

      foo
0    test
1  foo[b7
2    ba[r

df.foo.str.split('[').str[0]

0    test
1     foo
2      ba
Name: foo, dtype: object

Answer 3

import pandas as pd
df = pd.DataFrame({'foo':[x.split('[')[0] for x in ['a','b[b7','c']]})
print(df)

Answer 4

import pandas as pd
df=pd.DataFrame({'foo':['a','b[b7','c']} )
df["foo"] = df["foo"].str.replace("(\[.*)","")

以下是https://regex101.com/解释

1st Capturing Group (\[.*)
\[ matches the character [ literally (case sensitive)
.* matches any character (except for line terminators)
* Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)

这意味着它会寻找[。如果找到一个，它将删除[及其后面的所有字符。