以下是我的代码。
我知道为什么在变换期间发生错误。这是因为拟合和变换期间的特征列表不匹配。 我怎么解决这个问题?如何获得所有其他功能的0?
在此之后我想将它用于SGD分类器的部分拟合。
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import pandas as pd
from sklearn.preprocessing import OneHotEncoder
input_df = pd.DataFrame(dict(fruit=['Apple', 'Orange', 'Pine'],
color=['Red', 'Orange','Green'],
is_sweet = [0,0,1],
country=['USA','India','Asia']))
input_df
Out[1]:
color country fruit is_sweet
0 Red USA Apple 0
1 Orange India Orange 0
2 Green Asia Pine 1
filtered_df = input_df.apply(pd.to_numeric, errors='ignore')
filtered_df.info()
# apply one hot encode
refreshed_df = pd.get_dummies(filtered_df)
refreshed_df
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 3 entries, 0 to 2
Data columns (total 4 columns):
color 3 non-null object
country 3 non-null object
fruit 3 non-null object
is_sweet 3 non-null int64
dtypes: int64(1), object(3)
memory usage: 176.0+ bytes
Out[2]:
is_sweet color_Green color_Orange color_Red country_Asia \
0 0 0 0 1 0
1 0 0 1 0 0
2 1 1 0 0 1
country_India country_USA fruit_Apple fruit_Orange fruit_Pine
0 0 1 1 0 0
1 1 0 0 1 0
2 0 0 0 0 1
enc = OneHotEncoder()
enc.fit(refreshed_df)
Out[3]:
OneHotEncoder(categorical_features='all', dtype=<class 'numpy.float64'>,
handle_unknown='error', n_values='auto', sparse=True)
new_df = pd.DataFrame(dict(fruit=['Apple'],
color=['Red'],
is_sweet = [0],
country=['USA']))
new_df
Out[4]:
color country fruit is_sweet
0 Red USA Apple 0
filtered_df1 = new_df.apply(pd.to_numeric, errors='ignore')
filtered_df1.info()
# apply one hot encode
refreshed_df1 = pd.get_dummies(filtered_df1)
refreshed_df1
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 1 entries, 0 to 0
Data columns (total 4 columns):
color 1 non-null object
country 1 non-null object
fruit 1 non-null object
is_sweet 1 non-null int64
dtypes: int64(1), object(3)
memory usage: 112.0+ bytes
Out[5]:
is_sweet color_Red country_USA fruit_Apple
0 0 1 1 1
enc.transform(refreshed_df1)
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-6-33a6a884ba3f> in <module>()
----> 1 enc.transform(refreshed_df1)
~/anaconda3/lib/python3.6/site-packages/sklearn/preprocessing/data.py in transform(self, X)
2073 """
2074 return _transform_selected(X, self._transform,
-> 2075 self.categorical_features, copy=True)
2076
2077
~/anaconda3/lib/python3.6/site-packages/sklearn/preprocessing/data.py in _transform_selected(X, transform, selected, copy)
1810
1811 if isinstance(selected, six.string_types) and selected == "all":
-> 1812 return transform(X)
1813
1814 if len(selected) == 0:
~/anaconda3/lib/python3.6/site-packages/sklearn/preprocessing/data.py in _transform(self, X)
2030 raise ValueError("X has different shape than during fitting."
2031 " Expected %d, got %d."
-> 2032 % (indices.shape[0] - 1, n_features))
2033
2034 # We use only those categorical features of X that are known using fit.
ValueError: X has different shape than during fitting. Expected 10, got 4.
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答案 0 :(得分:5)
您需要LabelEncoder + OneHotEncoder,而不是pd.get_dummies()
,它可以存储原始值,然后在新数据上使用它们。
如下所示更改代码将为您提供所需的结果。
import pandas as pd
from sklearn.preprocessing import OneHotEncoder, LabelEncoder
input_df = pd.DataFrame(dict(fruit=['Apple', 'Orange', 'Pine'],
color=['Red', 'Orange','Green'],
is_sweet = [0,0,1],
country=['USA','India','Asia']))
filtered_df = input_df.apply(pd.to_numeric, errors='ignore')
# This is what you need
le_dict = {}
for col in filtered_df.columns:
le_dict[col] = LabelEncoder().fit(filtered_df[col])
filtered_df[col] = le_dict[col].transform(filtered_df[col])
enc = OneHotEncoder()
enc.fit(filtered_df)
refreshed_df = enc.transform(filtered_df).toarray()
new_df = pd.DataFrame(dict(fruit=['Apple'],
color=['Red'],
is_sweet = [0],
country=['USA']))
for col in new_df.columns:
new_df[col] = le_dict[col].transform(new_df[col])
new_refreshed_df = enc.transform(new_df).toarray()
print(filtered_df)
color country fruit is_sweet
0 2 2 0 0
1 1 1 1 0
2 0 0 2 1
print(refreshed_df)
[[ 0. 0. 1. 0. 0. 1. 1. 0. 0. 1. 0.]
[ 0. 1. 0. 0. 1. 0. 0. 1. 0. 1. 0.]
[ 1. 0. 0. 1. 0. 0. 0. 0. 1. 0. 1.]]
print(new_df)
color country fruit is_sweet
0 2 2 0 0
print(new_refreshed_df)
[[ 0. 0. 1. 0. 0. 1. 1. 0. 0. 1. 0.]]
答案 1 :(得分:-1)
您的编码器适用于refreshed_df
,其中包含10列,而您的refreshed_df1
仅包含4个,字面意思是错误中报告的内容。您要么删除未显示在refreshed_df1
上的列,要么只是将您的编码器适合新版refreshed_df
,该版本仅包含refreshed_df1
中显示的4列。