我正在尝试回复帖子表中发布的每个帖子的链接。我正在检查时,$stmt = $pdo->query('SELECT id, userid, postTitle, postDate, postUrl, votes FROM posts ORDER BY votes DESC');
while ($row = $stmt->fetch()) {
?>
<a href="<?php $row['postUrl'] ?>">Link</a>
<?php
}
标签内是否有正确的信息,但我无法点击它?对于这里发生的一些信息非常有用,我该如何解决?这就是我想要做的事情:
目前,我将链接文字作为链接无法点击。
Sub arraytest()
Dim myArray As Variant
Dim i As Integer
myArray = ActiveWorkbook.Worksheets("Semesters").ListObjects("tblSemester").DataBodyRange.Value
For i = 1 To UBound(myArray, 1)
myArray(i, 5) = "18/19"
myArray(i, 6) = "Fall"
Next
Worksheets("Sheet1").Range("A2").Resize(UBound(myArray, 1), UBound(myArray, 2)).Value = myArray
End Sub
答案 0 :(得分:3)
您忘记结束PHP标记或添加echo
,您必须在while循环开始时结束PHP标记,并在标记之后添加另一个PHP标记。或者你可以添加如下的回声!祝你好运!
尝试这个!
<?php
$stmt = $pdo->query('SELECT id, userid, postTitle, postDate, postUrl, votes FROM posts ORDER BY votes DESC');
while ($row = $stmt->fetch()) {
?>
<a href="<?php echo $row['postUrl']; ?>">Link</a>
<?php
}
?>