Question

我希望用户写下他们的用户名并查看他们的输入是否在我的表格中，但我不知道如何搜索他们的输入。

如何做到这一点（这是选择1的位置）？

import sqlite3

import sys

conn= sqlite3.connect('log_accounts.db')

c= conn.cursor()

def login():

    c.execute('CREATE TABLE IF NOT EXISTS account(forename, age, username , year_group, password)')
    c.execute("INSERT INTO account VALUES ('Hannah', '16', 'Han16', '11', '1234')")
    conn.commit()
    print("----------------------")
    print("| 1- Log in          |")
    print("| 2- Register        |")
    print("| 3- Exit            |")
    choice= input("Please select a choice :\n")
    if choice =='1':
        username= input("Please enter your username: \n")
        password= input("Please enter your password: \n")
        results=c.execute("SELECT username, password"
                          "FROM accounts WHERE username= ?", (username,))
        print(results)



    c.close()
    conn.close()
login()

Answer 1

execute()返回一个游标对象，您必须迭代该对象以获取行。每行都是一个包含列值的元组（在本例中为两个）：

results = c.execute("SELECT username, password FROM ...")
for row in results:
    print("found: name = {}, password = {}".format(row[0], row[1])
    break
else:
    print("not found")

Answer 2

```

c.execute('CREATE TABLE IF NOT EXISTS account(forename, age, username , 
           year_group, password)')
c.execute("INSERT INTO account VALUES ('Hannah', '16', 'Han16', '11', 
          '1234')")
conn.commit()
print("----------------------")
print("| 1- Log in          |")
print("| 2- Register        |")
print("| 3- Exit            |")
username= input("Please select a UserName:\n")
password= input("Please select a Password:\n")

cursor.execute(f"SELECT password FROM account WHERE username={username}")
results=cursor.fetchone()[0]
if results:
   if results==password:
      print("login success!")
   else:
      print("password is wrong")
else:
   print("username is wrong")

```

搜索用户输入

2 个答案: