我有以下字典列表:
test = [{'Date': datetime.datetime(2017, 12, 26, 0, 0),'Visitors': [{u'Owner_Name': u'Ashish Bainade', u'Unit_ID': u'1000', u'ID': u'Ashish ainade 119', u'In_Time': datetime.datetime(2017, 12, 26, 12, 13), u'Wing': u'Z'},{u'Owner_Name': u'Ashish Bainade', u'Unit_ID': u'102', u'ID': u'6976', u'In_Time': datetime.datetime(2017, 12, 26, 13, 15), u'Wing': u'B'}]}]
我想按键Visitors
按照下面的降序排序子词典In_Time
test = [{'Date': datetime.datetime(2017, 12, 26, 0, 0),'Visitors': [{u'Owner_Name': u'Ashish Bainade', u'Unit_ID': u'102', u'ID': u'6976', u'In_Time': datetime.datetime(2017, 12, 26, 13, 15), u'Wing': u'B'},{u'Owner_Name': u'Ashish Bainade', u'Unit_ID': u'1000', u'ID': u'Ashish ainade 119', u'In_Time': datetime.datetime(2017, 12, 26, 12, 13), u'Wing': u'Z'}]}]
我试图采用这种方法:
from operator import itemgetter
但我无法获得所需的输出,有什么方法或建议可以帮助我吗?
感谢任何帮助。
答案 0 :(得分:3)
只需对子词典test[0]['Visitors'] = sorted(test[0]['Visitors'], key = lambda x: x['In_Time'], reverse = True)
进行排序并将其分配回来。
itemgetter
如果您想使用from operator import itemgetter
test[0]['Visitors'] = sorted(test[0]['Visitors'], key=itemgetter('In_Time'), reverse=True)
:
[{'Date': datetime.datetime(2017, 12, 26, 0, 0),
'Visitors': [{u'ID': u'Ashish ainade 119',
u'In_Time': datetime.datetime(2017, 12, 26, 12, 13),
u'Owner_Name': u'Ashish Bainade',
u'Unit_ID': u'1000',
u'Wing': u'Z'},
{u'ID': u'6976',
u'In_Time': datetime.datetime(2017, 12, 26, 13, 15),
u'Owner_Name': u'Ashish Bainade',
u'Unit_ID': u'102',
u'Wing': u'B'}]}]
输入:
[{'Date': datetime.datetime(2017, 12, 26, 0, 0),
'Visitors': [{u'ID': u'6976',
u'In_Time': datetime.datetime(2017, 12, 26, 13, 15),
u'Owner_Name': u'Ashish Bainade',
u'Unit_ID': u'102',
u'Wing': u'B'},
{u'ID': u'Ashish ainade 119',
u'In_Time': datetime.datetime(2017, 12, 26, 12, 13),
u'Owner_Name': u'Ashish Bainade',
u'Unit_ID': u'1000',
u'Wing': u'Z'}]}]
输出:
android:permission="android.permission.BIND_JOB_SERVICE"