Question

我尝试使用发布请求将视频文件上传到我的服务器。

var file = new File(videoPath);
var uri = Uri.parse(tokenizedUri);
HttpClientRequest request = await new HttpClient().postUrl(uri);

await request.addStream(file.openRead());
var response = await request.close();

response.transform(utf8.decoder).forEach((string) {
  print(string); // handle data
});

但服务器无法获得它。为什么呢？

Answer 1

正确的方法是使用MultipartRequest：

    var uri = Uri.parse(url);
    var request = new MultipartRequest("POST", uri);

    var multipartFile = await MultipartFile.fromPath("package", videoPath);
    request.files.add(multipartFile);

    StreamedResponse response = await request.send();
    response.stream.transform(utf8.decoder).listen((value) {
      print(value);
    });

Answer 2

您可以使用 Dio 包。它支持大文件，对我来说效果很好。

sendFile(String kMainUrl, XFile file) async {
    String filePath = file.path;
    String fileName = 'any name';

    try {
      FormData formData = FormData.fromMap({
        "file":
        await MultipartFile.fromFile(filePath, filename:fileName),
      });
      Response response =
      await Dio().post(kMainUrl, data: formData);
      print("File upload response: $response");
      print(response.data['message']);
    } catch (e) {
      print("Exception Caught: $e");
    }
}

在Flutter中使用POST请求上传文件

2 个答案: