Question

我正在尝试通过发布请求将文件上传到amazon s3。麻烦的是，我不知道如何将请求格式化为多部分表单。

这就是我现在所拥有的：

content_type = "image/JPEG"
key = 'uploads/filename.jpg'
acl = "public-read"
bucket = None

params_raw = create_upload_data(content_type,key,acl,bucket)

params = { 'policy': params_raw['policy'],'acl':acl,'signature':params_raw['signature'],'key':params_raw['key'],'Content-Type':params_raw['Content-Type'],'AWSAccessKeyId':params_raw['AWSAccessKeyId'],'success_action_status':params_raw['success_action_status'],'binary': binary_data}
r = requests.post(params_raw['form_action'],data=params)

我认为我收到了错误的回复，因为它不是一个多部分表单，但这里是响应文本的样子：

{"request": "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<Error><Code>InvalidArgument</Code><Message>Conflicting query string parameters: acl, policy</Message><ArgumentName>ResourceType</ArgumentName><ArgumentValue>acl</ArgumentValue><RequestId>D558E016151E448F</RequestId><HostId>WT5aT0OOqJx3ziPgYFzjuTHJSERaCcuJG+y/acs6+l/mWVwO0MiH3lhWyBWIdhKr9BnhdIpkarw=</HostId></Error>"}

如何使用文件构建请求...它是基础64中的.jpg？

Answer 1

更改内容类型

就足够了

package com.example.akibmahmud.namota;

import android.app.AlertDialog;
import android.media.MediaPlayer;
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ScrollView;
import android.widget.TextView;


public class MainActivity extends ActionBarActivity implements MediaPlayer.OnCompletionListener {
    EditText et1,et2;
    private Button bt;
    ScrollView sv;
    TextView tv;
    private MediaPlayer mp;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        et1= (EditText) findViewById(R.id.firsteditText);
        et2= (EditText) findViewById(R.id.secondeditText);
        bt= (Button) findViewById(R.id.button);
        sv= (ScrollView) findViewById(R.id.scrollView);
        tv= (TextView) findViewById(R.id.textView);
       bt.setOnClickListener(new View.OnClickListener() {
           @Override
           public void onClick(View v) {
               String et11=et1.getText().toString();
               String et22=et2.getText().toString();
               if (!et11.equals("") && !et22.equals("")){
                   int input1=Integer.parseInt(et11);
                   int input2=Integer.parseInt(et22);
                   int i,k,r;
                   for (i = input1; i <=input1 ; i++) {
                       for (k =input2; k <= 50; k++) {
                           tv.setText(+i+"*"+k+"="+i*k+"/n");
                       }
                   }

               }else{
                   play();
               }
           }
       });
        setup();
    }

    private void play(){
        mp.start();
        bt.setEnabled(false);
    }
    private void loadClip(){
        try {
            mp=MediaPlayer.create(this,R.raw.ok);
            mp.setOnCompletionListener(this);
        }catch (Throwable t){
            goBlooey(t);
        }
    }
    private void setup(){
        loadClip();
        bt.setEnabled(true);
    }
    private void goBlooey(Throwable t){
        AlertDialog.Builder builder=new AlertDialog.Builder(this);
        builder
                .setTitle("Exception!")
                .setMessage(t.toString())
                .setPositiveButton("OK",null)
                .show();
    }


    @Override
    public void onCompletion(MediaPlayer mp) {
        setup();
    }
}

Answer 2

在这方面有一点点痛苦，但终于明白了。最后非常简单！

url = "https://yourbucket.s3.amazonaws.com"

#complete_path is the local server path to the file
files = {'file':open(complete_path,'rb')}

r = requests.post(url, data=params, files=files)

s3上传文件发布请求

2 个答案: