我需要在javascript中绘制类似于此处http://www.fordscorpio.co.uk/flatspot.htm的图形的扭矩曲线,最好使用g.raphael。欢迎任何建议。谢谢!
答案 0 :(得分:1)
您可以按如下方式创建自己的轴对象。 (已丢失此代码段的源/ gist网址,因此无法在其到期时提供信用)
axis = r.g.axis(85,230,310,null,null,4,2,["1", "2", "3", "4"], "|", 0);
axis.text.attr({font:"12px Arial", "font-weight": "regular", "fill": "#333333"});
// y-axis denoted by setting orientation to 1
axis2 = r.g.axis(40,230,300,0,400,10,1);
因此,创建一个包含两个系列的法线图,然后绘制另一个轴
否则,设置多个轴然后调整标签: -
var lines = r.g.linechart(10, 10, 300, 220, [[1, 2, 3, 4, 5, 6, 7],[3.5, 4.5, 5.5, 6.5, 7, 8]], [[12, 32, 23, 15, 17, 27, 22], [10, 20, 30, 25, 15, 28]], {nostroke: false, axis: "1 1 1 1", symbol: "o", smooth: true});
lines.axis[0].text.items[3].attr('text','my label');
答案 1 :(得分:-1)
http://g.raphaeljs.com/linechart.html
以下是删除了3个不相关图表的脚本:
window.onload = function () {
var r = Raphael("holder");
r.g.txtattr.font = "12px 'Fontin Sans', Fontin-Sans, sans-serif";
var x = [], y = [], y2 = [], y3 = [];
for (var i = 0; i < 1e6; i++) {
x[i] = i * 10;
y[i] = (y[i - 1] || 0) + (Math.random() * 7) - 3;
y2[i] = (y2[i - 1] || 150) + (Math.random() * 7) - 3.5;
y3[i] = (y3[i - 1] || 300) + (Math.random() * 7) - 4;
}
r.g.text(160, 10, "Symbols, axis and hover effect");
(function(){
var lines = r.g.linechart(10, 10, 300, 220, [[1, 2, 3, 4, 5, 6, 7],[3.5, 4.5, 5.5, 6.5, 7, 8]], [[12, 32, 23, 15, 17, 27, 22], [10, 20, 30, 25, 15, 28]], {nostroke: false, axis: "0 0 1 1", symbol: "o", smooth: true}).hoverColumn(function () {
this.tags = r.set();
for (var i = 0, ii = this.y.length; i < ii; i++) {
this.tags.push(r.g.tag(this.x, this.y[i], this.values[i], 160, 10).insertBefore(this).attr([{fill: "#fff"}, {fill: this.symbols[i].attr("fill")}]));
}
}, function () {
this.tags && this.tags.remove();
});
lines.symbols.attr({r: 3});
// lines.lines[0].animate({"stroke-width": 6}, 1000);
// lines.symbols[0].attr({stroke: "#fff"});
// lines.symbols[0][1].animate({fill: "#f00"}, 1000);
};
</script>