Question

是否可以在g.Raphaël条形图中为每个条形图赋予自己的颜色？

我完全可以改变系列的颜色。但我想要的是，每个系列的第一个结果是有相似的颜色，每个系列的第二个等等。

我找不到很多关于它的文档，我尝试了一些无头实验，但没有一个能达到我想要的效果。

Answer 1

您可以设置如下选项：

var custom_colors =["#ff0000","#00ff00","#0000ff","#ffff00","#ff00ff","#00ffff"];

r.barchart(x,y,width,height,[data], { colors: custom_colors });

其他选项

var options : {
    legend : [],
    stacked: false, //Use this to stack your bars instead of displaying them side by side
    type: "soft", //round, sharp, soft, square,
    colors : custom_colors
}

r.barchart(x,y,width,height,[data], options);

您可能想要在函数中定义颜色。您可以使用以下功能：

function _getColors() {
    var byndColors = ["#ffc000","#1d1d1d","#e81c6e","#7c7c7c","#00aff2","#aaaaaa","#611bc9"];

    //some random colors
    var randColors = ["#77efac","#364f8a","#60cb94","#cf263b","#2471bb","#7fc398","#d2c66a","#2109dc","#66ad29","#9a9754","#640cdf","#257683","#d51e05","#4bb36e","#e7408a","#1ef173","#1756bc","#cff215","#15c2fb","#f010ab","#844a0","#c34021","#3e4cf2","#8e2864","#a28f5c","#a9d528","#7b1e43","#a5401c","#829813","#691ccd"]

    //combine them
    return byndColors.concat(randColors);

}

并使用它：

r.barchart(x,y,width,height,[data], { colors: _getColors() });

Answer 2

您可以在attr

中更改每个路径的svg属性

r.barchart(x,y,width,length,[data]);

var colors =["#ff0000","#00ff00","#0000ff","#ffff00","#ff00ff","#00ffff","#552288","#228844","#a38643","#296583"];

// use jquery for easier way 
$("#holder svg path").each(function(index){
    $(this).attr("fill",colors[index]);
});

Answer 3

您需要指定一些颜色，然后确保数据是一个数组数组，其中内部数组的索引对于除索引之外的所有值都是0：

data = [[55, 0, 0], [0, 20, 0], [0, 0, 40]];

r.barchart(10, 10, 100, 220, data, {
    colors: [
        // Some colours
        "000-#d00-#900",
        "000-#f64-#c31",
        "000-#fc0-#c90",
        "000-#3a3-#070",
        "000-#2bc-#089",
        "000-#00d-#00a",
        "000-#808-#404",
        "000-#444-#000"
    ]
});

此处r是Raphael实例。见http://g.raphaeljs.com/barchart.html

g.raphael条形图每个酒吧的颜色不同？

3 个答案: