我遇到了碰撞,但是我希望我的代码可以工作,以便当鸟接触到这些块时,print('x')
。它正在这样做,但不是在鸟的正确位置。为长代码道歉,但它需要运行。
import random
import pygame
vec = pygame.math.Vector2
BLACK = (0,0,0)
RED = (255,0,0)
WIDTH = 500
HEIGHT = 400
pygame.init()
window = pygame.display.set_mode((WIDTH, HEIGHT))
pygame.display.set_caption('Flappy Bird')
clock = pygame.time.Clock()
class Bird():
def __init__(self):
self.skin = pygame.image.load('bird2.png')
self.rect = self.skin.get_rect()
self.rect.center = (WIDTH / 2, HEIGHT / 2)
self.vx = 0
self.vy = 0
self.pos = vec(WIDTH / 2, HEIGHT / 2)
self.vel = vec(0, 0)
self.acc = vec(0, 0)
def update(self):
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
window.fill(BLACK)
self.acc = vec(0, 0.7) #having 0.5 adds gravity
self.vy = 0
keys = pygame.key.get_pressed()
if keys[pygame.K_SPACE]:
self.vel.y = -7
if keys[pygame.K_LEFT]:
self.acc.x = -0.5 #change to y to add vertical motion
if keys[pygame.K_RIGHT]:
self.acc.x = 0.5 #change to y to add vertical motion
#applys friction
self.acc.x += self.vel.x * -0.08 #FRICTION
#motion equations
self.vel += self.acc
self.pos += self.vel + 0.5 * self.acc
self.rect.center = self.pos
window.blit(self.skin, self.pos)
class Pipe():
def __init__(self,x,y):
self.image = pygame.Surface((50,60))
self.image.fill(RED)
self.rect = self.image.get_rect(topleft=(x,y))
self.pos = vec(x,y)
def blit_pipe(self):
window.blit(self.image, self.pos)
def border_check():
if (flappy.pos.y)+32 > HEIGHT: #this is the very top of the flappy
print("You are under\n")
pygame.quit()
quit()
if flappy.pos.y < 0:
print("You are over\n") #this is the very top of the flappy
pygame.quit()
quit()
pipey = Pipe(300,200)
pipey.blit_pipe()
pipey2 = Pipe(100,200)
pipey2.blit_pipe()
flappy = Bird()
window.blit(flappy.skin, flappy.pos)
while True:
border_check()
flappy.update()
pipey.blit_pipe()
pipey2.blit_pipe()
if flappy.rect.colliderect(pipey.rect):
print('x')
clock.tick(30)
pygame.display.update()
答案 0 :(得分:4)
您需要在矩形的左上角处对图像进行blit。您可以将中心设置为self.pos
并将矩形作为blit位置传递(然后pygame使用左上角坐标),
self.rect.center = self.pos
window.blit(self.skin, self.rect)
或将topleft
属性设置为self.pos
,然后您仍然可以在self.pos
处对图像进行blit:
self.rect.topleft = self.pos
window.blit(self.skin, self.pos)
答案 1 :(得分:1)
在pygame中绘制矩形时,前两个参数是X和Y起点,接下来的两个参数是宽度和高度。这将从左上角绘制矩形。你需要做的是,如果鸟是图像的边缘,则有一个图像的边缘。然后你可以做类似的事情:
pygame.draw.rect(screen, red, [topLeftX, topLeftY, birdWidth, birdHeight])
另一种方法是,如果您无法修改图片,只需使用+
符号进行微调。