调用其他函数后,Arduino函数保持循环

时间:2017-12-24 10:33:17

标签: c++ arduino

我是使用c ++进行编码的初学者,我一直试图通过串行输入使LED引脚闪烁,但当我告诉它关闭时,它会一直闪烁。我认为问题出在代码的底部。

int ledPin = 13;
String readString;

void setup() {
  Serial.begin(115200);
  pinMode(ledPin, OUTPUT);
  Serial.println("Serial Blinker (Input 'on' to blink and 'off' to stop blinking)");
}
void loop() {
  readString = "";
  while (Serial.available()) {
    delay(3);
    char c = Serial.read();
    readString += c;
  }
  readString.trim();
  if (readString.length() > 0) {
    if (readString == "on") {
      Serial.println("switching on");
      next();
    }
  }
}
void next() {
  digitalWrite(ledPin, HIGH);
  delay(500);
  digitalWrite(ledPin, LOW);
  delay(500);
  digitalWrite(ledPin, HIGH);
  delay(500);
  digitalWrite(ledPin, LOW);
  delay(500);
  readString = "";
  while (Serial.available()) {
    delay(3);
    char c = Serial.read();
    readString += c;
  }
  readString.trim();
  if (readString.length() > 0) {
    if (readString == "off") {
      Serial.println("switching off");
      digitalWrite(ledPin, LOW);
    }
  }
  next();
}

1 个答案:

答案 0 :(得分:1)

试试此代码

 int ledPin = 13;
String readString;

void setup() {
  Serial.begin(115200);
  pinMode(ledPin, OUTPUT);
  Serial.println("Serial Blinker (Input 'on' to blink and 'off' to stop blinking)");
}
void loop() {
  readString = "";
  while (Serial.available()) {
    delay(3);
    char c = Serial.read();
    readString += c;
  }
  readString.trim();
  if (readString.length() > 0) {
    if (readString == "on") {
      Serial.println("switching on");
      next();
    }
    else if(readString == "off"){
      digitalWrite(ledPin, LOW);
    }
  }
}
void next() {
  digitalWrite(ledPin, HIGH);
  delay(500);
  digitalWrite(ledPin, LOW);
  delay(500);
  digitalWrite(ledPin, HIGH);
  delay(500);
  digitalWrite(ledPin, LOW);
  delay(500);
   readString = "";
  while (Serial.available()) {
    delay(3);
    char c = Serial.read();
    readString += c;
  }
  readString.trim();

    if (readString == "off") {
      Serial.print("off");
      digitalWrite(ledPin, LOW);
      off();
    }
    else {
            next();
    }

}

void off(){
  Serial.print("in off");
  digitalWrite(ledPin, LOW);

}