D编程语言中的就地基数排序

时间:2011-01-25 13:18:14

标签: sorting d

我正在尝试从In-Place Radix Sort工作中获取就地基数排序示例。到目前为止,我有这个:

import std.random;

void swap(ref string i,ref string j) {

  string tmp = i;
  i = j;
  j = tmp;
}

void radixSort(ref string[] seqs, size_t base = 0) {
    if(seqs.length == 0)
        return;

    size_t TPos = seqs.length, APos = 0;
    size_t i = 0;
    while(i < TPos) {
        if(seqs[i][base] == 'A') {
             swap(seqs[i], seqs[APos++]);
             i++;
        }
        else if(seqs[i][base] == 'T') {
            swap(seqs[i], seqs[--TPos]);
        } else i++;
    }

    i = APos;
    size_t CPos = APos;
    while(i < TPos) {
        if(seqs[i][base] == 'C') {
            swap(seqs[i], seqs[CPos++]);
        }
        i++;
    }
    if(base < seqs[0].length - 1) {
        radixSort(seqs[0..APos], base + 1);
        radixSort(seqs[APos..CPos], base + 1);
        radixSort(seqs[CPos..TPos], base + 1);
        radixSort(seqs[TPos..seqs.length], base + 1);
   }
}

void main(string[] args) {

  string [] sequences;

  for(int n=0;n<10;n++) {
    string seq;
    for(int i=0;i<10;i++) {
      int r = rand()%4;
      if(r == 0) seq = seq ~ "A";
      if(r == 1) seq = seq ~ "C";
      if(r == 2) seq = seq ~ "G";
      if(r == 3) seq = seq ~ "T";
    }
    sequences = sequences ~ seq;
  }

  writefln("Unsorted");
  for(size_t n=0;n<10;n++) {
    writefln(sequences[n]);
  }

  radixSort(sequences,0);

  writefln("Sorted");
  for(size_t n=0;n<10;n++) {
    writefln(sequences[n]);
  }
}

然而,这失败了:

radix.d(36): Error: slice expression seqs[0u..APos] is not a modifiable lvalue
radix.d(37): Error: slice expression seqs[APos..CPos] is not a modifiable lvalue
radix.d(38): Error: slice expression seqs[CPos..TPos] is not a modifiable lvalue
radix.d(39): Error: slice expression seqs[TPos..seqs.length] is not a modifiable lvalue

在Digital Mars D Compiler v1.066下。我猜切片是不可变的,但是......我该如何解决这个问题呢?

我是D的新手,并且很感兴趣让这个例子有效。

1 个答案:

答案 0 :(得分:7)

如果您想修改引用本身,则只需要ref。对于数组,这意味着更改长度或重新分配。由于你的基数排序是就地的,我不确定你为什么要这样。