如何在SQL Server中提取子字符串

时间:2011-01-25 12:50:59

标签: sql sql-server tsql

我有一个类似okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos

的字段

我想从数据中提取name = value

如何以有效的方式使用SQL Server 2008? 谢谢

4 个答案:

答案 0 :(得分:5)

试试这个

;
With MyTable as
(
    SELECT 'okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos' FullString
    UNION 
    SELECT 'fkgbokfgbo&name=fokdofkd&okfaos' FullString
    UNION 
    SELECT 'okbogkbogkbokgbok' FullString
),
PatternIndex as
(
    Select 
        FullString + '&' FullString, 
        CharIndex ('&name=', FullString) + 1 LocationOfEqualSign, 
        CharIndex ('&', FullString, CharIndex ('&name=', FullString)+1) as NextBreak
    from MyTable
),
SplitNameValue AS
(
    Select 
        FullString, 
        CASE 
            WHEN NextBreak <> 0 THEN 
            SubString (FullString, LocationOfEqualSign, NextBreak-LocationOfEqualSign) 
            ELSE '' END
        as NameValuePair
    From PatternIndex
)
SELECT * 
FROM SplitNameValue

返回

FullString                                                NameValuePair
--------------------------------------------------------- ---------------------------------------------------------
fkgbokfgbo&name=fokdofkd&okfaos                           name=fokdofkd
okbogkbogkbokgbok                                         
okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos name=fokdofkd

(3 row(s) affected)

答案 1 :(得分:1)

我认为这将有效:

Declare @String varchar(100)

Set @String = 'okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos'

Select SubString(@String,CharIndex('name=',@String),len(@String)) 

这会产生:

'名称= fokdofkd&安培; okfaos'

答案 2 :(得分:1)

SELECT 'name=' + SUBSTRING(field, CHARINDEX('name=', field), CHARINDEX('&', SUBSTRING(field, CHARINDEX('name=' ,field))))

答案 3 :(得分:1)

有些事情......

select substring(ColumnName, charindex('name=',ColumnName,1),len(ColumnName))