Question

我有一个包含数千行的表，如下所示（假名）：

C:\James\AAA(1) - C0001506 Mrs Michaela Hysell.pdf
C:\James\AAA(10) - C0001516 Mrs Delfina Cardoza.pdf
C:\James\AAA(11) - C0001517 Mrs Melony Pickle.pdf
C:\James\AAA(12) - C0001518 Mr Homer Guillot.pdf
C:\James\AAA(13) - C0001519 Mrs Lawerence Matis.pdf
C:\James\AAA(14) - C0001520 Mrs Yahaira Hausner.pdf

我需要做的是取出代码，以便列出：

到目前为止，我有这个：

select SUBSTRING ( FileName ,PatIndex('%-%', FileName + '5'),8)
from [FileNames]

返回我＆＃34; - C00015＆＃34;例如。

任何人都有任何想法如何使这个子串工作？

Answer 1

这将完成这项工作：

DECLARE @T TABLE ( STR VARCHAR(MAX));

INSERT INTO @T VALUES
('C:\James\AAA(1) - C0001506 Mrs Michaela Hysell.pdf'),
('C:\James\AAA(10) - C0001516 Mrs Delfina Cardoza.pdf'),
('C:\James\AAA(11) - C0001517 Mrs Melony Pickle.pdf'),
('C:\James\AAA(12) - C0001518 Mr Homer Guillot.pdf'),
('C:\James\AAA(13) - C0001519 Mrs Lawerence Matis.pdf'),
('C:\James\AAA(14) - C0001520 Mrs Yahaira Hausner.pdf');

SELECT *, 
       SUBSTRING(STR, CHARINDEX('-', STR, 0)+1, CHARINDEX('-', STR, 0)-8 ) AS Result
FROM @T

结果：

+--------------------------------------------------------+------------+
|                          STR                           |   Result   |
+--------------------------------------------------------+------------+
| C:\James\AAA(1) - C0001506 Mrs Michaela Hysell.pdf     |  C0001506  |
| C:\James\AAA(10) - C0001516 Mrs Delfina Cardoza.pdf    |  C0001516  |
| C:\James\AAA(11) - C0001517 Mrs Melony Pickle.pdf      |  C0001517  |
| C:\James\AAA(12) - C0001518 Mr Homer Guillot.pdf       |  C0001518  |
| C:\James\AAA(13) - C0001519 Mrs Lawerence Matis.pdf    |  C0001519  |
| C:\James\AAA(14) - C0001520 Mrs Yahaira Hausner.pd222f |  C0001520  |
+--------------------------------------------------------+------------+

<强> Demo

更新

以下是使用LEFT()，PATINDEX()和SUBSTRING()函数执行此操作的另一种方法：

SELECT *, 
       LEFT(SUBSTRING(STR, PATINDEX('%- %', STR) + 2, LEN(STR) ), 8) AS Result
FROM @T

复杂的SubString在String中提取String

1 个答案: