我正致力于解决欧拉项目3:
Description: The prime factors of 13195 are 5, 7, 13 and 29.
What is the largest prime factor of the number 600851475143 ?
这是我生成答案的代码。但是我需要一个整数类型来保存600851475143
。当我在Mac上的GCC上编译它时,我得到:
integer constant is too large for ‘long’ type".
我希望很长一段时间可以很容易地保持这个数字。我也试过让它没有签名。为什么我的代码不能保留那么少的代码,我该怎么做才能使它工作?
#include <iostream>
#include <vector>
using namespace std;
static bool IsPrimeFactor(int numToTest,int testNum,vector<int> factors)
{
if(numToTest%testNum==0) // is it a factor?
{
// see if it is a prime factor
for(unsigned int i=0; i < factors.size(); i++)
{
if(testNum%factors[i]==0) // see if this factor
{ //is divisble by one we have already
return false;
}
}
return true;
}
return false;
}
int main() {
unsigned long long numToTest=600851475143;
unsigned int testNum=2; // 0 and 1 are assumed
vector<int> factors;
while(testNum<numToTest) // don't go higher than the max num
{
if(IsPrimeFactor(numToTest,testNum,factors)) // is it a factor?
{
factors.push_back(testNum); // got through prime factors
} // and none divided it
testNum++;
}
for(unsigned int i=0; i < factors.size(); i++)
{
cout << "factor " <<factors[i] << endl;
}
cout<<"Highest factor: " << factors[factors.size()-1]<<endl;
return 0;
}
答案 0 :(得分:6)
检查this问题。你必须像这样指定你的文字:
600851475143LL
答案 1 :(得分:1)
正如@Space_C0wb0y所说,你需要为文字指定一个后缀。
另外,你的IsPrimeFactor
函数会出现问题 - 参数是整数,但正如你已经发现的那样,一个int甚至一个long都不足以存储你的数字我会反复传递......