Question

下面显示的代码是Tic tac toe游戏，其中有两个玩家（Player1和Player2是人类）。我现在在＆＃34; #Player 1 Play中的if else语句中出现问题＆＃34;和＃34; #Player 2现在播放＆＃34;代码的各个部分。确切地说，计算机总是认为每个盒子已经填充了除1,2,3,4,5,6,7,8,9之外的某些值，并且它一直显示消息＆＃34;该单元格已经是标记。请尝试另一个小区＆＃34;在嵌套的else语句中定义。有人可以告诉我如何解决这个问题吗？

board = [0,1,2,3,4,5,6,7,8,9]
print type(board[1])
def board_invoke():
print "| ",board[1], " | ", board[2], " | ", board[3], " | ", "\n", "-------------------", "\n", "| ", board[4], " | ",board[5], " | ", board[6], " | ", "\n", "-------------------", "\n", "| ",  board[7], " | ",board[8], " | ", board[9], " | "

def game_start():
Player1= raw_input("Select Player 1 between X or O : ")
if Player1 not in ('X','x','O','o'):
    print "That is not an expected player"
    game_start()
else:
    print "\nSince you have selected Player 1 as %s" %Player1
    print "\nThe Player 2 is assigned :",
    if Player1 in ('X','x'):
        Player2 = ("O")
    else:
        Player2 = ("X")
    print Player2
    print "\nThe game Starts now....\n"
    board_invoke()
    while (1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9) in board:

        # Winning Condition
        if board[1]==board[2]==board[3]==Player1:
            print Player1," wins"
            break
        elif board[4]==board[5]==board[6]==Player1:
            print Player1, " wins"
            break
        elif board[7]==board[8]==board[9]==Player1:
            print Player1, " wins"
            break
        elif board[1]==board[2]==board[3]==Player2:
            print Player2, " wins"
            break
        elif board[4]==board[5]==board[6]==Player2:
            print Player2, " wins"
            break
        elif board[7]==board[8]==board[9]==Player2:
            print Player2, " wins"
            break
        elif board[1]==board[5]==board[9]==Player1:
            print Player1, " wins"
            break
        elif board[3]==board[5]==board[7]==Player1:
            print Player1, " wins"
            break
        elif board[1]==board[5]==board[9]==Player2:
            print Player2, " wins"
            break
        elif board[3]==board[5]==board[7]==Player2:
            print Player2, " wins"
            break
        elif board[1]==board[4]==board[7]==Player1:
            print Player1, " wins"
            break
        elif board[2]==board[5]==board[8]==Player1:
            print Player1, " wins"
            break
        elif board[3]==board[6]==board[9]==Player1:
            print Player1, " wins"
            break
        elif board[1]==board[4]==board[7]==Player2:
            print Player2, " wins"
            break
        elif board[2]==board[5]==board[8]==Player2:
            print Player2, " wins"
            break
        elif board[3]==board[6]==board[9]==Player2:
            print Player2, " wins"
            break

        # Player 1 Plays now

        Cell_no = raw_input("Player 1 : Please select a number you want to mark....")
        Cell_no = int(Cell_no)

        if Cell_no not in board:
            print "Please enter a cell number within the scope of available cells"
        else:
            if 'X' or 'x' or 'O' or 'o' in board[Cell_no]:
                print "That cell is already marked. Please try another cell"
                continue
            else:
                board[Cell_no] = Player1
                board_invoke()

        # Player 2 Plays now

        Cell_no = raw_input("Player 2 : Please select a number you want to mark....")
        Cell_no = int(Cell_no)

        if Cell_no not in board:
            print "Please enter a cell number within the scope of available cells"
        else:
            if 'X' or 'x' or 'O' or 'o' in board[Cell_no]:
                print "That cell is already marked. Please try another cell"
                continue
            else:
                board[Cell_no] = Player2
                board_invoke()

    print "Do you want to play again ?"
    user_decision = raw_input("Please type Yes or No : ")
    if user_decision == ('YES' or 'Yes' or 'yes'):
        game_start()
    else:
        print "Ok. I take it that we will wrap up !"
        print "See you again !"



game_start()

Answer 1

您的if语句不完全正确。您正在评估：

else:
if 'X' or 'x' or 'O' or 'o' in board[Cell_no]:
    print "That cell is already marked. Please try another cell"

总是如此。 or个关键字在逻辑上组合了每个比较。然后，第一个比较语句将只是'X'，它不是null或0，因此总是如此。由于第一个陈述是真的，整个if语句都是正确的。

我经常看到人们开始学习编程。 If语句不能像人类句子一样编写。您必须将每个字符与变量进行比较。这是一个简单的（不是python特定且非常丑陋）解决您的问题的方法：

else:
 if 'X' == board[Cell_no] or 'x' == board[Cell_no] or 'O' == board[Cell_no] or 'o' == board[Cell_no]:
      print "That cell is already marked. Please try another cell"

更好的方法是转过来检查并将其与列表进行比较：

else:
 if board[Cell_no] in ['X','x', 'O', 'o']:
      print "That cell is already marked. Please try another cell"

Tic Tac toe程序错误（Python）

1 个答案: