我使用two edittexts
(Email
和password
)和2个按钮(submit
和viewdata
)创建了一个用于测试的应用。我正在调试这个应用程序,它工作正常。
我想通过添加一个Edittext
(Name
)来更新此应用,并升级SQLite Database
方法中的onUpgrade()
。代码如下所示。
public class DatabaseHelper extends SQLiteOpenHelper {
private static final String DATABASE_NAME="upgrade";
private static final int DATABASE_VERSION=2;
//details table details
public static final String TABLE_NAME_Details="details";
public static final String USERNAME="USERNAME";
public static final String PASSWORD="PASSWORD";
public static final String Name="Name"; //newly added column in version 2
public static final String TABLE_NAME_Details_temp="temp";
public static final String USERNAME_temp="USERNAME";
public static final String PASSWORD_temp="PASSWORD";
public static final String Name_temp="Name";
//create table statements for version 2
public static final String Create_Table_Details = "CREATE TABLE "
+ TABLE_NAME_Details + " (" + USERNAME + " TEXT PRIMARY KEY,"
+ PASSWORD + " TEXT ,"
+ Name + " TEXT"
+")";
/* creation for version 1
private static final String Create_Table_Details = "CREATE TABLE " +
TABLE_NAME_Details + "("
+ USERNAME + " TEXT PRIMARY KEY,"
+ PASSWORD + " TEXT"
+ ")";*/
//Alter table statements FOR onUpgrade()
//private static final String ALTER_Details = "ALTER TABLE " +
TABLE_NAME_Details + " ADD COLUMN" + Name + " TEXT";
public DatabaseHelper(Context context)
{
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
try{
db.execSQL(Create_Table_Details);
Log.d("database","installed successfully");
}catch (Exception e)
{
e.printStackTrace();
Log.e("/test","Exception due to"+e.toString());
}
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion)
{
String TEMP_CREATE_CONTACTS_TABLE = "CREATE TABLE " +
TABLE_NAME_Details_temp + "("
+ USERNAME_temp + " TEXT," + PASSWORD_temp + " TEXT )";
db.execSQL(TEMP_CREATE_CONTACTS_TABLE);
db.execSQL("INSERT INTO " + TABLE_NAME_Details_temp + " SELECT " +
USERNAME + ", "
+ PASSWORD + " FROM " + TABLE_NAME_Details);
db.execSQL("DROP TABLE "+ TABLE_NAME_Details);
String CREATE_CONTACTS_TABLE = "CREATE TABLE " + TABLE_NAME_Details + "("
+ USERNAME + " TEXT," + PASSWORD + " TEXT," + Name + " TEXT )";
db.execSQL(CREATE_CONTACTS_TABLE);
db.execSQL("INSERT INTO " + TABLE_NAME_Details + " SELECT " +
USERNAME_temp + ", "
+ PASSWORD_temp + ", " + Name_temp + ", " + null + " FROM " +
TABLE_NAME_Details_temp);
db.execSQL("DROP TABLE " + TABLE_NAME_Details);
}
public boolean insertData(String username, String password,String name)
{
try{
SQLiteDatabase db = this.getWritableDatabase();
ContentValues contentValues=new ContentValues();
contentValues.put(USERNAME,username);
contentValues.put(PASSWORD,password);
contentValues.put(Name,name);
long result=db.insertOrThrow(TABLE_NAME_Details, null, contentValues);
if(result==-1)
return false;
else
return true;
}catch(Exception e)
{
e.printStackTrace();
Log.e("/test","Exception due to"+e.toString());
return false;
}
}
//update value
public boolean updatePassword(String LoggedUsername)
{
SQLiteDatabase db = null;
try {
db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(PASSWORD, "test");
if (db.isOpen()) {
db.update(TABLE_NAME_Details, values, USERNAME + "='" +
LoggedUsername+"'",null);
return true;
}
else
return false;
} catch (Exception e) {
Log.d("eEmp/DBUpdateUser ", e.toString());
return false;
}
}
//getting data from database
public Cursor getAllData()
{
SQLiteDatabase db = this.getWritableDatabase();
Cursor res = db.rawQuery("select * from "+TABLE_NAME_Details,null);
return res;
}
}
我安装了第一个版本并正常工作然后卸载。
卸载后,安装第二个版本并存储数据。它也工作正常。
当我尝试在调试模式下使用第二个版本更新第一个版本时,应用程序已成功更新,并且第一个版本中输入的数据可见。当我试图将数据存储在第二版时,数据不会插入到sqlite数据库。为什么呢?
调试时,调用insert方法但是if(result==-1)
我得-1而不是1.所以,数据控制来自方法,数据没有插入数据库。
例如:在第一个版本中:我输入了用户名:stackoverflow
和密码stackoverflow
。
我将应用更新到第二版并成功更新。现在我输入了用户名:hello
密码:hello
名称:hello
,然后点击提交按钮。
之后如果我点击viewdata
按钮:它显示用户名:stackoverflow
密码stackoverflow
名称:null。但不显示第二版中插入的数据。
任何帮助将不胜感激。请帮助我找到正确的解决方案。
谢谢。
答案 0 :(得分:1)
有一个打字错误检查你的列名是db是
public static final String Name="Name"; //newly added column in version 2
并且您正在使用NAME_
在sqlite中插入数据时更改它
试试这个
try{
SQLiteDatabase db = this.getWritableDatabase();
ContentValues contentValues=new ContentValues();
contentValues.put(USERNAME,username);
contentValues.put(PASSWORD,password);
contentValues.put(Name,name);
long result=db.insert(TABLE_NAME_Details, null, contentValues);
if(result==-1)
return false;
else
return true;
}catch(Exception e)
{
e.printStackTrace();
Log.e("/test","Exception due to"+e.toString());
return false;
}
答案 1 :(得分:1)
试试这个..
// Upgrading database
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
String TEMP_CREATE_CONTACTS_TABLE = "CREATE TABLE " + TEMP_TABLE_CONTACTS + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT," + KEY_ADDRESS + " TEXT)";
db.execSQL(TEMP_CREATE_CONTACTS_TABLE);
// Create an temporaty table that can store data of older version
db.execSQL("INSERT INTO " + TEMP_TABLE_CONTACTS + " SELECT " + KEY_ID + ", "
+ KEY_NAME + ", " + KEY_ADDRESS + " FROM " + TABLE_CONTACTS);
// Insert data into temporary table from existing older version database (that doesn't contains ADDRESS2 //column)
db.execSQL("DROP TABLE "+ TABLE_CONTACTS);
// Remove older version database table
String CREATE_CONTACTS_TABLE = "CREATE TABLE " + TABLE_CONTACTS + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT," + KEY_ADDRESS + " TEXT," + KEY_ADDRESS2 + " TEXT )";
db.execSQL(CREATE_CONTACTS_TABLE);
// Create new table with ADDRESS2 column
db.execSQL("INSERT INTO " + TABLE_CONTACTS + " SELECT " + KEY_ID + ", "
+ KEY_NAME + ", " + KEY_ADDRESS + ", " + null + " FROM " + TEMP_TABLE_CONTACTS);
// Insert data ffrom temporary table that doesn't have ADDRESS2 column so left it that column name as null.
db.execSQL("DROP TABLE " + TEMP_TABLE_CONTACTS);
}
答案 2 :(得分:0)
不要在onCreate()
和onUpgrade()
中捕获异常。如果出现问题,则该方法不能正常返回。通常返回意味着一切都成功,数据库模式可以使用。
请注意onUpgrade()
ALTER TABLE
中缺少的空格:
private static final String ALTER_Details = "ALTER TABLE " + TABLE_NAME_Details + " ADD COLUMN" + NAME_ + " TEXT";
介于COLUMN
和NAME_
之间。这会导致升级的数据库无法正常工作。全新安装仅通过onCreate()
,onUpgrade()
中的错误未公开。
使用insertOrThrow()
代替insert()
来获取更多有用的错误消息,例如"没有这样的列"。