Question

我现在有一个带有标签的数组和带有键和值的2个对象。有了这些数据，我想用对象格式化一个新数组。

示例：

const years = ["5", "6", "7", "8", "9"];
const left = {5: 2, 6: 1, 7: 22};
const right = {6: 1, 7: 1, 8: 22, 9: 1};

//Output should be
const newArr = [
    {
        label: 5 year,
        left: 2,
        right: null,
    },
    {
        label: 6 year,
        left: 1,
        right: 1,
    },
    {
        label: 7 year,
        left: 22,
        right: 1,
    },
    {
        label: 8 year,
        left: null,
        right: 22,
    },
    {
        label: 9 year,
        left: null,
        right: 1,
    },
]

如果其中一个对象没有对象中的year（key），则该值为null。

Answer 1

使用map

var replaceFn = ( obj, key ) => !obj.hasOwnProperty( key ) ? null : obj[ key ]; 

var output = years.map( s => ({ 
         label : s + " years", 
         left : replaceFn( left, s ), 
         right : replaceFn( right, s ) 
}));

<强>演示

＆＃13;

var years = ["5", "6", "7", "8", "9"];
var left = {5: 2, 6: 1, 7: 22, 8: undefined};
var right = {6: 1, 7: 1, 8: 22, 9: 1};

console.log( left.hasOwnProperty( 8 ) );

var replaceFn = ( obj, key ) => !obj.hasOwnProperty( key ) ? null : obj[ key ]; 

var output = years.map( s => ({ 
         label : s + " years", 
         left : replaceFn( left, s ), 
         right : replaceFn( right, s ) 
}));

console.log( output );

＆＃13;

Answer 2

只需遍历years数组并动态获取其他两个对象的值：

const years = ["5", "6", "7", "8", "9"];
const left = {5: 2, 6: 1, 7: 22};
const right = {6: 1, 7: 1, 8: 22, 9: 1};

const newArr = [];

years.forEach(year => {
  newArr.push({
    label: `${year} year(s)`,
    right: right[year] || null,
    left: left[year] || null,
  })
});

示例：https://repl.it/repls/StingyIrritatingCrayfish

Answer 3

您可以检查密钥是否在对象（in operator）中并取值，否则取null。

var years = ["5", "6", "7", "8", "9"],
    left = { 5: 2, 6: 1, 7: 22 },
    right = { 6: 1, 7: 1, 8: 22, 9: 1 },
    result = years.map(k => ({
        label: k + ' year',
        left: k in left ? left[k] : null,
        right: k in right ? right[k] : null
    }));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

格式化新结构中的数据

3 个答案: