我有一个像这样的对象类型列:
quote['SellTime'].astype(str).astype(int)
t2 = quote['SellTime'].astype(str).str.zfill(6)
quote['SellTime'] = pd.to_datetime(t2, format='%H%M%S').dt.time
我想将其转换为日期时间(datetime64 [ns])格式。
我已完成以下代码:
quote['SellTime'].head()
0 09:45:20
1 09:45:38
2 09:46:09
3 09:46:15
4 09:46:17
Name: SellTime, dtype: object
但它仍然是对象类型:
page.ts
答案 0 :(得分:1)
如果需要date
s:
datetime
quote['SellTime'] = pd.to_datetime(t2, format='%H%M%S')
print (quote)
SellTime
0 1900-01-01 09:45:20
1 1900-01-01 09:45:38
2 1900-01-01 09:46:09
3 1900-01-01 09:46:15
4 1900-01-01 09:46:17
或者更好的是将时间转换为timedelta
s:
quote['SellTime']=pd.to_timedelta(pd.to_datetime(t2,format='%H%M%S').dt.strftime('%H:%M:%S'))
print (quote['SellTime'])
0 09:45:20
1 09:45:38
2 09:46:09
3 09:46:15
4 09:46:17
Name: SellTime, dtype: timedelta64[ns]
因为如果将日期时间转换为time
s:
quote['SellTime'] = pd.to_datetime(t2, format='%H%M%S').dt.time
print (quote['SellTime'].dtype)
object
print (quote['SellTime'])
0 09:45:20
1 09:45:38
2 09:46:09
3 09:46:15
4 09:46:17
Name: SellTime, dtype: object
print (quote['SellTime'].apply(type))
0 <class 'datetime.time'>
1 <class 'datetime.time'>
2 <class 'datetime.time'>
3 <class 'datetime.time'>
4 <class 'datetime.time'>
Name: SellTime, dtype: object