Question

我目前正在使用python3和afplay编写音频播出系统。我遇到了一个问题，我不能让它自动转到播放列表中的下一首歌，同时仍允许用户控制。

for i in range(metadata["length"] - start):
        i += start

        curr = songs[i]
        play(directory + curr)

        paused_bool = False

        while True:
            clear()

            print("Currently playing track #" + str(i+1) + ", called '" + curr + "', from playlist '" + metadata["name"] + "'.")
            command = input("What would you like to do? 'play', 'stop/exit', 'pause', or 'skip/next': ")

            if command == "play" or command == "pl":
                if not paused_bool:
                    print("It is already playing.")

                else:
                    play(directory + curr)


            elif command == "stop" or command == "st" or command == "quit" or command == "q" or command == "exit":
                stop()
                return

            elif command == "pause" or command == "p" or command == "pa":
                if paused_bool:
                    print("The audio shall remain paused.")

                paused_bool = True
                stop()

            elif command == "move the hell on" or command == "skip" or command == "next" or command == "n" or command == "s" or command == "":
                stop()
                break


            clear()

以上是播放文件夹中每首歌曲的代码。我希望能够使用＆＃34; next＆＃34;手动转到下一首歌曲。命令，但也经过一段时间后自动转到下一个，特别是歌曲的长度。

我尝试使用threading包，但是当我无法从函数中断while循环时遇到问题：

for i in range(metadata["length"] - start):
        i += start

        curr = songs[i]
        play(directory + curr)

        paused_bool = False

        while True:
            clear()

            def auto():
                time.sleep( length( curr_song ) )
                stop() # stop() & break goes to the next song
                break

            thread = Thread(target = auto, args = [])
            thread.start()

            print("Currently playing track #" + str(i+1) + ", called '" + curr + "', from playlist '" + metadata["name"] + "'.")
            command = input("What would you like to do? 'play', 'stop/exit', 'pause', or 'skip/next': ")

            if command == "play" or command == "pl":
                if not paused_bool:
                    print("It is already playing.")

                else:
                    play(directory + curr)


            elif command == "stop" or command == "st" or command == "quit" or command == "q" or command == "exit":
                stop()
                return

            elif command == "pause" or command == "p" or command == "pa":
                if paused_bool:
                    print("The audio shall remain paused.")

                paused_bool = True
                stop()

            elif command == "move the hell on" or command == "skip" or command == "next" or command == "n" or command == "s" or command == "":
                stop()
                break


            clear()

我很抱歉这个问题非常令人难以置信，但任何帮助都会受到高度赞赏。

Answer 1

您可能想要使用scheduler。它会稍微改变你的代码的逻辑，但它可能会更有用。

默认情况下，您可以安排播放下一首歌曲的事件（使用scrollTo()或// Scroll To Query. submit = () => { try { const { text } = this.state // Text. const target = this[text] // Target. // Locate Target. target.measure((framex, framey, width, height, x, y) => { // Scroll To Target. this.ScrollView.scrollTo({x, y, animated: true}) }) } catch (error) { return console.log(error) } }）。您可以获得当前歌曲的运行时间，以便知道何时安排下一首歌曲。如果＆＃34; next＆＃34;如果选中，您将enter上一个事件并安排另外两个：1）一个新的立即执行，播放下一首歌曲，2）播放以下歌曲。

在python中经过一段时间后执行任务

1 个答案: