Question

我的代码如下：

我试图写下＆＃39; x＆＃39;使用＆＃34;打开＆＃34;进入文件，但是当我写回信时：

x = ["a","b","c"]
list = x
for i in list:
    x=("\nletter",i,"and\n")
    i+=i

with open("teste.txt","w") as f:
    f.write(str(x))

并且应该返回：

('\nletter', 'c', 'and\n')

当我更换＆＃39; x＆＃39;通过print（）工作正常，但在python上打印结果。这是代码：

letter a and


letter b and


letter c and

如何在文件上写入打印结果？谢谢！

Answer 1

每次循环都会覆盖x的值，而不是附加到它。使用print函数会更容易：

x = ["a", "b", "c"]
with open("test.txt", "w") as f:
    for letter in x:
        print("letter {} and".format(letter), file=f)

Answer 2

试试这样：

x = ["a","b","c"]
x = ["\nletter" + i + "and\n" for i in x]

with open("teste.txt","w") as f:
    for line in x:
        f.write(line)

Answer 3

只编辑一个循环：

x = ["a", "b", "c"]

with open("teste.txt", "w") as f:
    for i in x[:-1]:
        f.write("letter " + i + " and" + '\n' + '\n')
    f.write("letter " + x[-1] + " and")

Answer 4

在for循环的每次迭代中，您重新创建变量，而不是将值添加到其中。

Answer 5

您需要使用第一个列表来创建另一个列表：

dotnet --info

或以更简洁的方式：

letters = ["a", "b", "c"]
sentences = []
for i in letters:
    sentences.append("\nletter " + i + " and\n")

with open("teste.txt", "w") as f:
    for sentence in sentences:
        f.write(sentence)

Answer 6

这是你的问题：

list = x

稍后更改x时，您也在更改list ...

Python - 写同样的打印结果

6 个答案: