我需要一个只包含逗号分隔的字符串的列表。我不知道如何在python中做到这一点。
以下是我的示例输入：
BluetoothAdapter mBluetoothAdapter = BluetoothAdapter.getDefaultAdapter();
ListView lView;
ArrayList<String> devNameList, devAddressList;
private ListAdapter arrayAdapter;
private ConnectThread mConnectThread;
private BluetoothSocket mmSocket = null;
private static final UUID MY_UUID = UUID.fromString("00001101-0000-1000-8000-00805F9B34FB");
private final static int REQUEST_ID = 2;
// Create a BroadcastReceiver for ACTION_FOUND.
private final BroadcastReceiver mReceiver = new BroadcastReceiver() {
public void onReceive(Context context, Intent intent) {
String action = intent.getAction();
if (BluetoothDevice.ACTION_FOUND.equals(action)) {
// Discovery has found a device. Get the BluetoothDevice
// object and its info from the Intent.
BluetoothDevice device = intent.getParcelableExtra(BluetoothDevice.EXTRA_DEVICE);
String devName = device.getName();
String devAddress = device.getAddress();
devAddressList.add(devAddress);
if (devName == null){
devName = device.getAddress();
}
devNameList.add(devName);
lView.setAdapter(arrayAdapter);
}
}
};
private class ConnectThread extends Thread {
ConnectThread(BluetoothDevice device) {
BluetoothSocket tmp = null;
try {
// Get a BluetoothSocket to connect with the given BluetoothDevice.
// MY_UUID is the app's UUID string, also used in the server code.
tmp = device.createRfcommSocketToServiceRecord(MY_UUID);
} catch (IOException e) {
Toast.makeText(getBaseContext(), "ERROR: Socket's create() method failed", Toast.LENGTH_SHORT).show();
}
mmSocket = tmp;
}
public void run() {
try {
// Connect to the remote device through the socket. This call blocks
// until it succeeds or throws an exception.
mmSocket.connect();
} catch (IOException connectException) {
// Unable to connect; close the socket and return.
try {
mmSocket.close();
} catch (IOException closeException) {
Toast.makeText(getBaseContext(), "ERROR: Could not close the client socket",
Toast.LENGTH_SHORT).show();
}
return;
}
// The connection attempt succeeded. Perform work associated with
// the connection in a separate thread.
manageMyConnectedSocket();
}
// Closes the client socket and causes the thread to finish.
void cancel() {
try {
mmSocket.close();
} catch (IOException e) {
Toast.makeText(getBaseContext(), "ERROR: Could not close the client socket",
Toast.LENGTH_SHORT).show();
}
}
}
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_add_new_device);
requestPermissions();
lView = findViewById(R.id.discList);
devNameList = new ArrayList<>();
devAddressList = new ArrayList<>();
arrayAdapter = new ArrayAdapter<>(this, android.R.layout.simple_list_item_1, devNameList);
if (mBluetoothAdapter.isDiscovering()){
mBluetoothAdapter.cancelDiscovery();
}
// Register for broadcasts when a device is discovered.
IntentFilter filter = new IntentFilter(BluetoothDevice.ACTION_FOUND);
registerReceiver(mReceiver, filter);
mBluetoothAdapter.startDiscovery();
lView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
String devName = devNameList.get(position);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
if((Objects.equals(devName, "HC-06"))|| (Objects.equals(devName, "00:21:13:00:97:6A"))){
Toast.makeText(AddNewDevice.this, "Please wait...", Toast.LENGTH_SHORT).show();
mBluetoothAdapter.cancelDiscovery();
String address = devAddressList.get(position);
BluetoothDevice device = mBluetoothAdapter.getRemoteDevice(address);
mConnectThread = new ConnectThread(device);
mConnectThread.run();
}
else{
Toast.makeText(AddNewDevice.this, "Please connect to an HC-06 device.", Toast.LENGTH_SHORT).show();
}
}
else {
if("HC-06".equals(devName) || "00:21:13:00:97:6A".equals(devName)){
Toast.makeText(AddNewDevice.this, "Please wait...", Toast.LENGTH_SHORT).show();
mBluetoothAdapter.cancelDiscovery();
String address = devAddressList.get(position);
BluetoothDevice device = mBluetoothAdapter.getRemoteDevice(address);
mConnectThread = new ConnectThread(device);
mConnectThread.run();
}
else{
Toast.makeText(AddNewDevice.this, "Please connect to an HC-06 device.", Toast.LENGTH_SHORT).show();
}
}
}
});
}
private void requestPermissions(){
int androidVersion = Build.VERSION.SDK_INT;
if (androidVersion >= 23){
ActivityCompat.requestPermissions(this,
new String[]{Manifest.permission.ACCESS_FINE_LOCATION,
Manifest.permission.ACCESS_COARSE_LOCATION,
}, REQUEST_ID);
}
}
@Override
protected void onDestroy() {
super.onDestroy();
unregisterReceiver(mReceiver);
mBluetoothAdapter.cancelDiscovery();
}
private void manageMyConnectedSocket() {
mConnectThread.cancel();
finish();
}
我的预期输出是：
[(0, '0.897*"allah" + 0.120*"indeed" + 0.117*"lord" + 0.110*"said" + 0.101*"people" + 0.093*"upon" + 0.083*"shall" + 0.082*"unto" + 0.072*"believe" + 0.070*"earth"'), (1, '0.495*"lord" + 0.398*"said" + -0.377*"allah" + 0.253*"shall" + 0.241*"people" + 0.236*"unto" + 0.196*"indeed" + 0.131*"upon" + 0.118*"come" + 0.109*"thou"'), (2, '-0.682*"lord" + 0.497*"shall" + 0.349*"unto" + 0.125*"thou" + 0.125*"thee" + -0.098*"indeed" + 0.092*"come" + -0.092*"said" + 0.092*"people" + 0.080*"truth"')]
答案 0 :(得分：2)
您可以尝试正则表达式：
一线解决方案：
import re
pattern = r'[a-z]+'
string_1 = [(0,'0.897*"allah" + 0.120*"indeed" + 0.117*"lord" + 0.110*"said" + 0.101*"people" + 0.093*"upon" + 0.083*"shall" + 0.082*"unto" + 0.072*"believe" + 0.070*"earth"')]
print([k if isinstance(k, int) else [i.group() for i in re.finditer(pattern, str(string_1))] for i in string_1 for k in i])
输出：
[0, ['allah', 'indeed', 'lord', 'said', 'people', 'upon', 'shall', 'unto', 'believe', 'earth']]
详细解决方案：
final_list=[]
for i in string_1:
for k in i:
if isinstance(k,int):
final_list.append(k)
else:
for i in re.finditer(pattern, str(string_1)):
final_list.append(i.group())
print(final_list)
正则表达式解释：
**[a-z]**
Match a single character present in the list below [a-z]+
**+ Quantifier** —
Matches between one and unlimited times, as many times as possible,
giving back as needed (greedy)
根据您的要求编辑回答：
import re
pattern = r'[a-z]+'
string_1 = [(0, '0.897*"allah" + 0.120*"indeed" + 0.117*"lord" + 0.110*"said" + 0.101*"people" + 0.093*"upon" + 0.083*"shall" + 0.082*"unto" + 0.072*"believe" + 0.070*"earth"'), (1, '0.495*"lord" + 0.398*"said" + -0.377*"allah" + 0.253*"shall" + 0.241*"people" + 0.236*"unto" + 0.196*"indeed" + 0.131*"upon" + 0.118*"come" + 0.109*"thou"'), (2, '-0.682*"lord" + 0.497*"shall" + 0.349*"unto" + 0.125*"thou" + 0.125*"thee" + -0.098*"indeed" + 0.092*"come" + -0.092*"said" + 0.092*"people" + 0.080*"truth"')]
print([k if isinstance(k, int) else [i.group() for i in re.finditer(pattern, str(i))] for i in string_1 for k in i])
输出：
[0, ['allah', 'indeed', 'lord', 'said', 'people', 'upon', 'shall', 'unto', 'believe', 'earth'], 1, ['lord', 'said', 'allah', 'shall', 'people', 'unto', 'indeed', 'upon', 'come', 'thou'], 2, ['lord', 'shall', 'unto', 'thou', 'thee', 'indeed', 'come', 'said', 'people', 'truth']]
如果您想要更具体的结果，那么您可以尝试：
print([[k if isinstance(k, int) else tuple([i.group() for i in re.finditer(pattern, str(k))]) for k in i] for i in string_1])
输出：
[[0, ('allah', 'indeed', 'lord', 'said', 'people', 'upon', 'shall', 'unto', 'believe', 'earth')], [1, ('lord', 'said', 'allah', 'shall', 'people', 'unto', 'indeed', 'upon', 'come', 'thou')], [2, ('lord', 'shall', 'unto', 'thou', 'thee', 'indeed', 'come', 'said', 'people', 'truth')]]
答案 1 :(得分：0)
转换的关键是挑选双引号中的单词。为此，我会使用正则表达式。我的解决方案看起来像这样：
from pprint import pprint
import re
def transform(t):
return (t[0],) + tuple(re.findall(r'"(\w+)"', t[1]))
inlist = [
(0, '0.897*"allah" + 0.120*"indeed" + 0.117*"lord" + 0.110*"said" + 0.101*"people" + 0.093*"upon" + 0.083*"shall" + 0.082*"unto" + 0.072*"believe" + 0.070*"earth"'),
(1, '0.495*"lord" + 0.398*"said" + -0.377*"allah" + 0.253*"shall" + 0.241*"people" + 0.236*"unto" + 0.196*"indeed" + 0.131*"upon" + 0.118*"come" + 0.109*"thou"'),
(2, '-0.682*"lord" + 0.497*"shall" + 0.349*"unto" + 0.125*"thou" + 0.125*"thee" + -0.098*"indeed" + 0.092*"come" + -0.092*"said" + 0.092*"people" + 0.080*"truth"'),
]
outlist = map(transform, inlist)
pprint(outlist)
输出：
[(0, 'allah', 'indeed', 'lord', 'said', 'people', 'upon', 'shall', 'unto', 'believe', 'earth'),
(1, 'lord', 'said', 'allah', 'shall', 'people', 'unto', 'indeed', 'upon', 'come', 'thou'),
(2, 'lord', 'shall', 'unto', 'thou', 'thee', 'indeed', 'come', 'said', 'people', 'truth')]