我有一个活动,目前显示谷歌API工作正常的酒吧列表,我试图得到它,以便通过onclick解析“名称”和其他细节。目前它打开一个新活动,但我无法获得我用putExtra发送的解析JSON。 任何帮助赞赏。
Bars.java
public class Bars extends AppCompatActivity {
private String TAG = Bars.class.getSimpleName();
private ProgressDialog pDialog;
ListView lv;
// URL to get Results JSON
private static String url = "https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=40.785091,-73.968285&radius=1000&type=restaurant,bar,food,point_of_interest&keyword=bar&opennow=true&key=MYAPICODE";
ArrayList<HashMap<String, String>> resultsList;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_bars);
resultsList = new ArrayList<>();
lv = (ListView) findViewById(R.id.list);
new Getresults().execute();
}
//Async task class to get json by making HTTP call
private class Getresults extends AsyncTask<Void, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(Bars.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();
}
@Override
protected Void doInBackground(Void... arg0) {
HttpConnect sh = new HttpConnect();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url);
Log.e(TAG, "Response from url: " + jsonStr);
if (jsonStr != null) {
try {
JSONObject jsonObj = new JSONObject(jsonStr);
// Getting JSON Array node
JSONArray results = jsonObj.getJSONArray("results");
// looping through All results
for (int i = 0; i < results.length(); i++) {
JSONObject c = results.getJSONObject(i);
String name = c.getString("name");
String vicinity = c.getString("vicinity");
String rating = c.getString("rating");
// tmp hash map for single resu
HashMap<String, String> result = new HashMap<>();
// adding each child node to HashMap key => value
result.put("name", name);
result.put("vicinity", vicinity);
result.put("rating", rating) ;
// adding result to result list
resultsList.add(result);
}
} catch (final JSONException e) {
Log.e(TAG, "Json parsing error: " + e.getMessage());
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Json parsing error: " + e.getMessage(),
Toast.LENGTH_LONG)
.show();
}
});
}
} else {
Log.e(TAG, "Couldn't get json from server.");
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Couldn't get json from server. Check LogCat for possible errors!",
Toast.LENGTH_LONG)
.show();
}
});
}
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
/**
* Updating parsed JSON data into ListView
* */
ListAdapter adapter = new SimpleAdapter(
Bars.this, resultsList,
R.layout.list_item, new String[]{"name", "vicinity",
"rating" }, new int[]{name,
R.id.vicinity, R.id.rating});
lv.setAdapter(adapter);
// on lick listener to send name position
lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> adapterView, View view, int position, long id) {
Intent newActivity = new Intent(Bars.this,
SecondActivity.class);
newActivity.putExtra("position", position);
newActivity.putExtra("name", name);
startActivity(newActivity);
}
});
}
}
}
如您所见,最后一部分将“name”和“position”发送到secondActivity Class,如下所示
public class SecondActivity extends AppCompatActivity {
String name;
Intent getName;
Bundle extras;
TextView name1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_second);
String name = getIntent().getStringExtra("name");
getName = this.getIntent();
extras = getName.getExtras();
// Intent intent = getIntent();
// String name = intent.getStringExtra( name: "name");
}
public void name(View view){
name1 = (TextView)findViewById(R.id.name);
getIntent().getStringExtra("name");
}
}
答案 0 :(得分:0)
我看不到你初始化名字的位置。但是我可以在你的ListAdapter adapter = new SimpleAdapter(
Bars.this, resultsList,
R.layout.list_item, new String[]{"name", "vicinity",
"rating" }, new int[]{name,
R.id.vicinity, R.id.rating});
块中看到你编写了这段代码
name
在上面的代码中,您提到int
为int[]{name,R.id.vicinity, R.id.rating});
。看到这一行。
intent.getStringExtra('name')
因此,在第二项活动中调用hash
,您无法获得名称的价值。
答案 1 :(得分:0)
您需要从adapterView访问适配器,然后按位置获取hashMap并拉出项目
@Override public void onItemClick(AdapterView<?> adapterView, View view, int position, long id) {
ListAdapter adapter = (ListAdapter) adapterView.getAdapter()
HashMap<String, String> map = (HashMap) adapter.getItem(position)
String name = map.get("name") // may be a null
Intent newActivity = new Intent(Bars.this, SecondActivity.class);
newActivity.putExtra("position", position);
newActivity.putExtra("name", name);
startActivity(newActivity);
}