Question

我解析了一个XML文件并检索了以下JSON对象。问题是json中有破折号，导致迭代对象的问题。不幸的是，我无法摆脱他们。

$(function() {
  let json = JSON.parse('{"app-app":{"$":{},"notneeded":"123","mapped":{"$":{},"match-match":[{"$":{},"name":"Foo 1","url":"/Bar 1"},{"$":{},"name":"Foo 2","url":"/Bar 2"},{"$":{},"name":"Foo 3","url":"Bar 3"}]},"Nothing":"123"}}');

  var foo = Object.keys(json['app-app']['mapped']['match-match']).length;
  for (var i = 0; i < foo; i++) {
    console.log(json['app-app']['mapped']['match-match'][i].name);
    console.log(json['app-app']['mapped']['match-match'][i].url);
  }
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

我想遍历该对象并提取每个“匹配”子项。像这样：

return [
            {
                name: 'Foo 1',
                url:  'Bar 1'
            },
            [...]
       ]

提前谢谢你。

Answer 1

您可以简单地使用Array.prototype.map()来迭代json数组并返回自定义结构，如下所示：

$(function() {
  let json = JSON.parse('{"app-app":{"$":{},"notneeded":"123","mapped":{"$":{},"match-match":[{"$":{},"name":"Foo 1","url":"/Bar 1"},{"$":{},"name":"Foo 2","url":"/Bar 2"},{"$":{},"name":"Foo 3","url":"Bar 3"}]},"Nothing":"123"}}');


  var result = json['app-app']['mapped']['match-match'].map(function(item) {
    return {
      "name": item.name,
      "url": item.url
    };
  });
  console.dir(result);

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

它会给你预期的结果。

Answer 2

＆＃13;

let json = JSON.parse('{"app":{"$":{},"notneeded":"123","mapped":{"$":{},"match":[{"$":{},"name":"Foo 1","url":"/Bar 1"},{"$":{},"name":"Foo 2","url":"/Bar 2"},{"$":{},"regex":"Foo 3","configuration":"Bar 3"}]},"Nothing":"123"}}');
console.log(json['app']['mapped']['match']);

＆＃13;

迭代JSON-Object Array

2 个答案: