为什么这样保留ORA-00907:缺少右括号
CREATE VIEW LAPORAN_POSTINGANBULANAN (BULAN_TAHUN,JUMLAH POSTING)
AS
SELECT TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM') AS "BULAN_TAHUN",
COUNT(*) AS "JUMLAHPOSTING"
FROM POST (
GROUP BY TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM')
ORDER BY TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM') ASC);
答案 0 :(得分:0)
不需要paranthesis来包装组,因为它在语法上是错误的。 尝试删除它,如下所示它应该工作
CREATE VIEW LAPORAN_POSTINGANBULANAN (
BULAN_TAHUN
,JUMLAH POSTING
)
AS
SELECT TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM') AS "BULAN_TAHUN"
,COUNT(*) AS "JUMLAHPOSTING"
FROM POST
GROUP BY TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM')
ORDER BY TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM') ASC;
答案 1 :(得分:0)
视图没有参数或输出规范。因此我写的如下:
CREATE VIEW LAPORAN_POSTINGANBULANAN AS
SELECT TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM') AS "BULAN_TAHUN",
COUNT(*) AS "JUMLAHPOSTING"
FROM POST
GROUP BY TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM')
ORDER BY TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM') ASC;
答案 2 :(得分:0)
使用派生表简化代码,您不必多次重写CREATE VIEW LAPORAN_POSTINGANBULANAN (BULAN_TAHUN, JUMLAH_POSTING) AS
SELECT "BULAN_TAHUN", COUNT(*) AS "JUMLAHPOSTING"
FROM
(
SELECT TO_CHAR(POST.TANGGAL_POSTING, 'YYYY-MM') AS "BULAN_TAHUN"
FROM POST
) DT
GROUP BY "BULAN_TAHUN"
ORDER BY "BULAN_TAHUN" ASC
部分:
emulator