Question

我正在尝试在SQL中使用此语句创建一个表，但它表示缺少右括号。

这是声明

CREATE TABLE Bk_Jobs ( 
        Job_ID Int (20) Job_Title Varchar (255), 
        Min_Salary Decimal (25), 
        Max_Salary Decimal (25), 
);

Answer 1

CREATE TABLE Bk_Jobs ( 
      Job_ID INT PRIMARY KEY
    , Job_Title VARCHAR(255)
    , Min_Salary DECIMAL(25)
    , Max_Salary DECIMAL(25)
);

Answer 2

将int（20）更改为int < 设置逗号：Job_ID Int , Job_Title Varchar (255)

CREATE TABLE Bk_Jobs ( 
        Job_ID Int,
        Job_Title Varchar (255), 
        Min_Salary Decimal (25), 
        Max_Salary Decimal (25)
);

Answer 3

您在最后一栏中有一个额外不必要的逗号，将其删除。你也错过了Job_ID定义后的逗号。 INT没有大小，因此将int(20)更改为int

CREATE TABLE Bk_Jobs ( 
        Job_ID Int, --missed this one
        Job_Title Varchar (255), 
        Min_Salary Decimal (25), 
        Max_Salary Decimal (25), 
);
                               | here, this one is unnecessary.

Answer 4

你也可以尝试添加昏迷betwin Job_ID Int（20）和Job_Title Varchar（255）

Answer 5

这句话必须更好：

CREATE TABLE Bk_Jobs ( 
    Job_ID Int (20),
    Job_Title Varchar (255), 
    Min_Salary Decimal (25), 
    Max_Salary Decimal (25) 
);

Answer 6

有时编程错误可能有点滑稽。他们有时像我们一样无能为力：p

你在开头就错过了一个逗号，最后还有一个额外的逗号。

<?php
// Array which will hold all analyzed lines
$uniqueEntries = array();
$dublicatedEntries = array();
$delimiter = ',';
$file = 'test.csv';

//Open the file
if (($handle = fopen($file, "r")) !== false) {
    // read each line into an array
    while (($data = fgetcsv($handle, 8192, $delimiter)) !== false) {
        // build a "line" from the parsed data
        $line = join($delimiter, $data);

        //If the line content has ben discovered before - save to duplicated and skip the rest..
        if (isset($uniqueEntries[$line])){
            dublicatedEntries[] = $line;
            continue;
        }

        // save the line
        $uniqueEntries[$line] = true;
    }
    fclose($handle);
}

// build the new content-data
$contents = '';
foreach ($uniqueEntries as $line => $bool) $contents .= $line . "\r\n";

// save it to a new file
file_put_contents("test_unique.csv", $contents);
?>

创建表时出现错误“缺少右括号”

6 个答案: