Question

我有一个dicts列表

[
  {"day":"10", "car":"bmw", "count":"3"},
  {"day":"10", "car":"audi", "count":"2"},
  {"day":"10", "car":"jeep", "count":"4"},
  {"day":"11", "car":"bmw", "count":"6"},
  {"day":"11", "car":"audi", "count":"7"},
  {"day":"11", "car":"jeep", "count":"8"},
]

我想将它转换为这样（所需的输出）

[
      {"day":"10", "bmw":"3","audi":"2","jeep":"4"},
      {"day":"11","bmw":"6","audi":"7","jeep":"8"},
]

这就是我所做的。是否有更好和最佳的方法来实现这一目标。

def dl():
    list_of_dicts = [
            {"day":"10", "car":"bmw", "count":"3"},
            {"day":"10", "car":"audi", "count":"2"},
            {"day":"10", "car":"jeep", "count":"4"},
            {"day":"11", "car":"bmw", "count":"6"},
            {"day":"11", "car":"audi", "count":"7"},
            {"day":"11", "car":"jeep", "count":"8"},
            ]

    result = []
    data = {}

    for item in list_of_dicts:

        if not data.get(item["day"], False):    
            data[item["day"]] = []
            data[item["day"]].append({item["car"]:item["count"]})

        else:
            data[item["day"]].append({item["car"]:item["count"]})

    for key in data:
        new_dict = {}
        new_dict["day"] = key
        for item in data[key]:
            new_dict.update(item)
        result.append(new_dict)

    print result
    return result

dl()

如果问题不正确，有人请帮助我

更正此问题。我是初学者

Answer 1

使用itertools.groupby根据当天分组，然后为每一天创建一个新的词典：

list_of_dicts = [
  {"day":"10", "car":"bmw", "count":"3"},
  {"day":"10", "car":"audi", "count":"2"},
  {"day":"10", "car":"jeep", "count":"4"},
  {"day":"11", "car":"bmw", "count":"6"},
  {"day":"11", "car":"audi", "count":"7"},
  {"day":"11", "car":"jeep", "count":"8"},
]

# to use groupby the list must be sorted
list_of_dicts.sort(key=operator.itemgetter("day"))

result_list = []
for day, dicts_for_that_day in itertools.groupby(list_of_dicts, key=operator.itemgetter("day")):
    day_dict = {'day': day}
    day_dict.update({d['car']: d['count'] for d in dicts_for_that_day})
    result_list.append(day_dict)

print(result_list)

如何分组dicts列表？

1 个答案: