Question

我需要将其他参数传递给芹菜和弦中的回调函数。（ Celery版本：4.1.0（latentcall）和Python 2.7 ）

考虑以下示例：

program.py

from tasks import get_stock_info, call_back
from celery import group, chord

def chord_queue():
    header = (get_stock_info.subtask((delay,)) for delay in [4, 5, 4])
    callback = call_back.subtask()
    header1 = (get_stock_info.subtask((delay,)) for delay in [4, 4, 4])
    res = chord(header,queue='susanoo_dev')(callback)
    res1 = chord(header1,queue='susanoo_core')(callback)
    print(res.get())
    print(res1.get())
    print("We are done")

if __name__ == '__main__':
    chord_queue()

tasks.py

from pandas_datareader import data
from celery_app import app
import time

@app.task
def get_stock_info(delay):
    print('hello Celery--------')
    time.sleep(delay)
    print('Whats up')
    return 10

@app.task
def call_back(num):
    print("Everything is done------")
    print("Everything is done------")
    return sum(num)

celery_app.py

from celery import Celery
from kombu import Queue

app = Celery('tasks', broker='amqp://my_user:my_pass@localhost/my_vhost', backend='redis://localhost:6379/0')

CELERY_CONFIG = {
    'CELERY_DEFAULT_QUEUE': 'default',
    'CELERY_QUEUES': (Queue('dev'), Queue('core'),)
}

app.conf.update(**CELERY_CONFIG)

现在在这种情况下，当和弦被调用并且在所有3 get_stock_info 任务完成之后， call_back 被调用，值 10 ，这是 get_stock_info 的返回值自动传递。现在连同返回值我还想传递一个额外的参数，将一个字符串称为＆＃34; abcd＆＃34;到回调函数。

我该怎么做？

我已按照某些博客/ SO答案等建议尝试这样做。

program.py

def chord_queue():
    header = (get_stock_info.subtask((delay,)) for delay in [4, 5, 4])
    callback = call_back.subtask(kwargs={'my_str' : 'abcd'})
    header1 = (get_stock_info.subtask((delay,)) for delay in [4, 4, 4])
    res = chord(header,queue='susanoo_dev' )(callback)
    res1 = chord(header1,queue='susanoo_core')(callback)
    print(res.get())
    print(res1.get())
    print("We are done")

tasks.py

@app.task
def call_back(num, my_str):
    print("Everything is done------")
    print("Everything is done------")
    print my_str
    return my_str, sum(num)

但这似乎不起作用并引发以下错误：

celery.backends.base.ChordError：回调错误：TypeError（＆＃34; call_back（）得到了一个意外的关键字参数＆＃39; my_str＆＃39;＆＃34;，）

Answer 1

得到了答案。感谢一位帮助我的朋友。在上述解决方案中所做的一切都是在my_str的定义中没有将call_back()定义为关键字参数。

所以工作解决方案是：

<强> program.py

def chord_queue():
    header = (get_stock_info.subtask((delay,)) for delay in [4, 5, 4])
    callback = call_back.subtask(kwargs={'my_str' : 'abcd'})
    header1 = (get_stock_info.subtask((delay,)) for delay in [4, 4, 4])
    res = chord(header,queue='susanoo_dev' )(callback)
    res1 = chord(header1,queue='susanoo_core')(callback)
    print(res.get())
    print(res1.get())
    print("We are done")

<强> task.py

@app.task
def call_back(num, my_str=None):
    print("Everything is done------")
    print("Everything is done------")
    print my_str
    return my_str, sum(num)

它没有任何问题，按预期工作。

将其他参数传递给Celery和弦中的回调函数

1 个答案: