对于以下查询:
select count(distinct email_address)
from
(
select distinct email_address,
case when elq_activity_type='EmailSend' then 1 else 0 end 'Sends',
case when elq_activity_type='Bounceback' then 1 else 0 end 'Bounces',
case when elq_activity_type='EmailOpen' then 1 else 0 end 'Opens',
case when elq_activity_type='EmailClickthrough' then 1 else 0 end 'Clicks'
from elq_stg_activity
) a
having sum(sends-bounces)>0
having子句似乎没有做任何事情。我究竟做错了什么? 需要获取向其发送电子邮件的所有唯一电子邮件(发送 - 退回)。 谢谢!
答案 0 :(得分:1)
我想你想要这个:
select count(email_address)
from (select email_address,
sum(case when elq_activity_type = 'EmailSend' then 1 else 0 end) Sends,
sum(case when elq_activity_type = 'Bounceback' then 1 else 0 end) as Bounces,
sum(case when elq_activity_type = 'EmailOpen' then 1 else 0 end) as Opens,
sum(case when elq_activity_type = 'EmailClickthrough' then 1 else 0 end) as Clicks
from elq_stg_activity
group by email_address
) a
where sends = bounces;
您的查询存在许多问题。这是我能想到的唯一明智的解释。