Question

我是php编码新手

我创建了包含用户名和密码的登录页面，登录网页显示，当我输入用户和密码时出现错误，我发现很多方法，但我找不到任何解决方案，它＆＃39 ; s不工作，

image here

这是我错误的地方

这是登录代码

<?php include('server.php');?>)
<!DOCTYPE html>
<html>
<head>
<title> user registration system using php</title>
<link rel ="stylesheet" type="text/css" href="style.css">
</head>
<body>
    <div class ="header">
        <h2> login</h2>
    </div>
    <form method="post" action="login.php">
    <?php include('errors.php'); ?>
        <div class ="input-group">
            <label>Username</label>
            <input type = "text" name = "Username">
        </div>

        <div class ="input-group">
            <label>password</label>
            <input type = "text" name = "password">
        </div>
        <div class ="input-group">
            <button type ="submit" name ="register" class="btn">login</button>
            </div>
            <p>
                not yet a member? <a href="register.php">sign up</a>
            </p>
    </form>
    </body>
    </html>

servercode：

<?php
session_start();
$username = "";
$email = "";
$errors = array();
$db = mysqli_connect('localhost','root','','registration');
//print_r(!empty($_POST['registration']));exit;

if (empty($_POST['registration'])){

    $username = ($_POST['username']);
    $email = ($_POST['email']);
    $password = ($_POST['password']);
    //echo 'Hi';
if (empty($username)) {
    array_push($errors, "username is required");
}
if (empty($email)) {
    array_push($errors, "email is required");
}
if (empty($password)) {
    array_push($errors, "password is required");


}

if (count($errors) == 0) {

    $sql = "INSERT INTO users (username,email,password) VALUES('$username','$email','$password')";
mysqli_query($db,$sql);
$_SESSION['username'] = $username;
$_SESSION['success'] = "you are now logged in";
header('location: index.php');

}
}

if(isset($_POST['login'])) {
    $username = ($_POST['username']);

    $password = ($_POST['password']);
    //echo 'Hi';
if (empty($username)) {
    array_push($errors, "username is required");
}

if (empty($password)) {
    array_push($errors, "password is required");

}
if (count($errors)==0) {
    $query = "SELECT * FROM users where username = '$username' AND password ='$password'";
    $result = mysqli_query($db,$query);
    if(mysqli_num_rows($result) == 1) {

        $_SESSION['username'] = $username;
$_SESSION['success'] = "you are now logged in";
header('location: index.php');
}else{
    array_push($errors, "wrong username/password combination");
        header('location: login.php');
}
    }
}


if(isset($_GET['logout'])) {
    session_destroy();
    unset($_SESSION['username']);
    header('location: login.php');
}
?>

Answer 1

签入Html表单，您将名称命名为Username，在服务器端，您使用username获取值。有帽子和小写字母的问题。以html格式删除用户名中的U的大写字母并替换为u。

如果用户登录到登录页面，则会出现错误，并且不会登录

1 个答案: